Advertisements
Advertisements
Question
Advertisements
Solution
AIC to Ohm's law;
V=IR
Here, V = 200 volt and I= 11 A
R = `"V"/"I" = 200/11 = 18.2 Omega`
APPEARS IN
RELATED QUESTIONS
Calculate the number of electrons constituting one coulomb of charge.
You can given one hundred 1 Ω resistors. What is the smallest and largest resistance you can make in a circuit using these?
A cell supplies a current of 1.2 A through two 2 Ω resistors connected in parallel. When the resistors are connected in series, it supplies a current of 0.4 A. Calculate:
(i) the internal resistance and (ii) e.m.f. of the cell.
If a charge of 420 C flows through a conducting wire in 5 minutes what is the value of the current?
Define the following:
Super conductors
If the potential differences between two parts of a thundercloud is 10s V,
what is the amount of energy given up during the passage of 20 coulombs?
(a)2x10-7J
(b)200J
(c)Sx106 j
(d)2x 109J
(e)2x 1010 J
Calculate the current through a 60 W lamp rated 250 V. If the line voltage falls to 200 V, how is power consumed by the bulb affected?
Three heaters each rated 250 W, 100 V are connected in parallel to a 100 V supply. Calculate :
The total current taken from the supply
At the time of short circuit, the electric current in the circuit ______.
Define an electric current.
