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60 Joules of Heat Was Dissipated in a Resistor When 20 C Flowed for 5 S. Calculate: (A) P.D. Across the Resistor, - Physics

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Question

60 joules of heat was dissipated in a resistor when 20 C flowed for 5 s. Calculate:
(a) P.d. across the resistor,
(b) Resistance of the resistor, and
(c) Average power dissipated in the resistor.

Numerical
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Solution

Given, heat dissipated= 60 joules, charge Q = 20 C, time t= 5s

(a) P.d. across the rsistor, V = `"W"/"Q"= 60/20 = 3 "V"`

(b) Power = `"W"/"t" = "V"^2/"R"`

R = `"V"^2 xx "t"/"W" = (3)^2 xx 5/60 = 0.75 Omega`

(c) Power dissipated, P = `"W"/"t" = 60/5 = 12 "watt"`

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Chapter 4: Current Electricity - Exercise 4 [Page 212]

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Frank Physics - Part 2 [English] Class 10 ICSE
Chapter 4 Current Electricity
Exercise 4 | Q 7 | Page 212

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