Advertisements
Advertisements
प्रश्न
60 joules of heat was dissipated in a resistor when 20 C flowed for 5 s. Calculate:
(a) P.d. across the resistor,
(b) Resistance of the resistor, and
(c) Average power dissipated in the resistor.
Advertisements
उत्तर
Given, heat dissipated= 60 joules, charge Q = 20 C, time t= 5s
(a) P.d. across the rsistor, V = `"W"/"Q"= 60/20 = 3 "V"`
(b) Power = `"W"/"t" = "V"^2/"R"`
R = `"V"^2 xx "t"/"W" = (3)^2 xx 5/60 = 0.75 Omega`
(c) Power dissipated, P = `"W"/"t" = 60/5 = 12 "watt"`
APPEARS IN
संबंधित प्रश्न
1 A = _________ mA
- 102
- 103
- 10-3
- 10-6
How many milliamperes as there in 1 ampere?
Compare how an ammeter and a voltmeter are connected in a circuit.
A p.d. of 6 V is applied to two resistors of 3 Ω and 6 Ω connected in parallel. Calculate:
(a) the combined resistance
(b) the current flowing in the main circuit
(c) the current flowing in the 3 Ω resistor.
Define the term resistivity.
A fuse is a short piece of wire of high ______ and low ______.
For current to flow, one needs art open circuit.
In electrolytes, the ions carrying charge move toward:
