Advertisements
Advertisements
प्रश्न
60 joules of heat was dissipated in a resistor when 20 C flowed for 5 s. Calculate:
(a) P.d. across the resistor,
(b) Resistance of the resistor, and
(c) Average power dissipated in the resistor.
Advertisements
उत्तर
Given, heat dissipated= 60 joules, charge Q = 20 C, time t= 5s
(a) P.d. across the rsistor, V = `"W"/"Q"= 60/20 = 3 "V"`
(b) Power = `"W"/"t" = "V"^2/"R"`
R = `"V"^2 xx "t"/"W" = (3)^2 xx 5/60 = 0.75 Omega`
(c) Power dissipated, P = `"W"/"t" = 60/5 = 12 "watt"`
APPEARS IN
संबंधित प्रश्न
An electric circuit consisting of a 0.5 m long nichrome wire XY, an ammeter, a voltmeter, four cells of 1.5 V each and a plug key was set up.
(i) Draw a diagram of this electric circuit to study the relation between the potential difference maintained between the points 'X' and 'Y' and the electric current flowing through XY.
If the current passing through a conductor is doubled, what will be the change in heat produced
The work done in moving unit positive charge across two points in an electric circuit is a measure of
A charge of 80 C flows in a conductor for 2 minutes.
(a) Calculate the current flowing through the conductor.
(b) If the current through a heater is 4 A what charge must be passing in 8 seconds?
Find the effective resistance in the following circuit diagrams (Fig.):
Explain with the help of a diagram how does 'short circuiting' occur in an electric kettle.
How is direction of current related to the direction of flow of electrons?
