Advertisements
Advertisements
प्रश्न
60 joules of heat was dissipated in a resistor when 20 C flowed for 5 s. Calculate:
(a) P.d. across the resistor,
(b) Resistance of the resistor, and
(c) Average power dissipated in the resistor.
Advertisements
उत्तर
Given, heat dissipated= 60 joules, charge Q = 20 C, time t= 5s
(a) P.d. across the rsistor, V = `"W"/"Q"= 60/20 = 3 "V"`
(b) Power = `"W"/"t" = "V"^2/"R"`
R = `"V"^2 xx "t"/"W" = (3)^2 xx 5/60 = 0.75 Omega`
(c) Power dissipated, P = `"W"/"t" = 60/5 = 12 "watt"`
APPEARS IN
संबंधित प्रश्न
What is the unit of electric current?
You can given one hundred 1 Ω resistors. What is the smallest and largest resistance you can make in a circuit using these?
If the lamps are both the same in the figure given below and if A1 reads 0.50 A, what do A2, A3, A4 and A5 read?
Two resistors of 2.0 Ω and 3.0 Ω are connected (a) in series (b) in parallel, with a battery of 6.0 V and negligible internal resistance. For each case draw a circuit diagram and calculate the current through the battery.
A current of 0.2 A flows through a wire whose ends are at a potential difference of 15 V. Calculate:
(i) The resistance of the wire, and
(ii) The heat energy produced in 1 minute.
Assertion (A): Electric current will not flow between two charged bodies when connected if their charges are the same.
Reason (R): Current is the rate of flow of charge.
