Two Resistors of 2.0ω and 3.0ω Are Connected (A) in Series (B) in Parallel, with a Battery of 6.0 V and Negligible Internal Resistance. for Each Case Draw a Circuit Diagram and Calculate th

प्रश्न

Two resistors of 2.0 Ω and 3.0 Ω are connected (a) in series (b) in parallel, with a battery of 6.0 V and negligible internal resistance. For each case draw a circuit diagram and calculate the current through the battery.

संख्यात्मक

उत्तर

(a) In Series -

R₁ = 2 Ω

R₂ = 3 Ω

R = R₁ + R₂ = 2 + 3 = 5 Ω

V = 6 V

`"I" = "V"/"R"`

I `= 6/5`

I = 1.2 A

(b) In Parallel -

R₁ and R₂ are connected in parallel

`1/"R" = 1/"R"_1 + 1/"R"_2`

`1/"R" = 1/2+1/3`

`1/"R" = 5/6`

R = `6/5` = 1.2 Ω

V = 6V

I `= "V"/"R"`

`= 6/1.2`

= 5 A

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संबंधित प्रश्‍न

Choose the correct alternative and rewrite the following sentence.

When the resistance of a conductor increases, the current will ________ increase.

(a) With the help of a circuit diagram, obtain the relation for the equivalent resistance of two resistances connected in parallel.
(b) In the circuit diagram shown below, find:

(i) Total resistance.
(ii) Current shown by the ammeter A