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प्रश्न
Two resistors of 2.0 Ω and 3.0 Ω are connected (a) in series (b) in parallel, with a battery of 6.0 V and negligible internal resistance. For each case draw a circuit diagram and calculate the current through the battery.
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उत्तर
(a) In Series -
R1 = 2 Ω
R2 = 3 Ω
R = R1 + R2 = 2 + 3 = 5 Ω
V = 6 V
`"I" = "V"/"R"`
I `= 6/5`
I = 1.2 A
(b) In Parallel -
R1 and R2 are connected in parallel
`1/"R" = 1/"R"_1 + 1/"R"_2`
`1/"R" = 1/2+1/3`
`1/"R" = 5/6`
R = `6/5` = 1.2 Ω
V = 6V
I `= "V"/"R"`
`= 6/1.2`
= 5 A
संबंधित प्रश्न
How many microamperes are there in 1 ampere?
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(c) In which circuit, if one bulb blows out, all other will stop glowing?
Which effect of current is utilised in an electric light bulb?
A given wire of resistance 1 Ω is stretched to double its length. What will be its new resistance?
The following table shows the current in Amperes and potential differences in Volts.
- Find the average resistance.
- What will be the nature of the graph between the current and potential difference? (Do not draw a graph.)
- Which law will the graph prove? Explain the law.
| V (volts) | I (amp) |
| 4 | 9 |
| 5 | 11.25 |
| 6 | 13.5 |
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(a) Describe what will happen when th e swi tch K is cl osed for severa l
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Problems for practice:
If 5A current flows through a circuit, then convert the current in terms of microampere?
