Advertisements
Advertisements
Question
Two resistors of 2.0 Ω and 3.0 Ω are connected (a) in series (b) in parallel, with a battery of 6.0 V and negligible internal resistance. For each case draw a circuit diagram and calculate the current through the battery.
Advertisements
Solution
(a) In Series -
R1 = 2 Ω
R2 = 3 Ω
R = R1 + R2 = 2 + 3 = 5 Ω
V = 6 V
`"I" = "V"/"R"`
I `= 6/5`
I = 1.2 A
(b) In Parallel -
R1 and R2 are connected in parallel
`1/"R" = 1/"R"_1 + 1/"R"_2`
`1/"R" = 1/2+1/3`
`1/"R" = 5/6`
R = `6/5` = 1.2 Ω
V = 6V
I `= "V"/"R"`
`= 6/1.2`
= 5 A
RELATED QUESTIONS
One coulomb of charge flows through any cross-section of a conductor in 1 second. What is the current flowing through the conductor?
The p.d. across a 3 Ω resistor is 6 V. The current flowing in the resistor will be:
(a) `1/2A`
(b) 1 A
(c) 2 A
(d) 6 A
If the current passing through a conductor is doubled, what will be the change in heat produced
Which effect of current is utilised in an electric light bulb?
An electric iron is rated 750 W, 230 V. Calculate the electrical energy consumed by the press in 16 hours.
Study the following circuit and find out:
(i) Current in 12 Ω resistor.
(ii) The difference in the readings of A1 and A2, if any.
An electrical gadget can give an electric shock to its user under certain circumstances. Mention any two of these circumstances.
An electric bulb is marked 100 W, 250 V. How much current will the bulb draw if connected to a 250 V supply?
Match the following:
| 1. | 1 mA | a. | series |
| 2. | 1 pA | b. | ohmmeter |
| 3. | Ammeter | c. | 10-6 ampere |
| 4. | Electrical resistivity | d. | 10-3 ampere |
