English

Calcium carbide is used for the artificial ripening of fruits. Actually the fruit ripens because of the heat evolved while calcium carbide reacts with the moisture.

Advertisements
Advertisements

Question

Calcium carbide is used for the artificial ripening of fruits. Actually the fruit ripens because of the heat evolved while calcium carbide reacts with the moisture. During this reaction calcium hydroxide and acetylene gas are formed. If 200 cm3 of acetylene is formed from a certain mass of calcium carbide, find the volume of oxygen required and carbon dioxide formed during the complete combustion. The combustion reaction can be represented as below.

\[\ce{2C2H2_{(g)} + 5O2_{(g)}-> 4CO2_{(g)} + 2H2O_{(g)}}\]

Numerical
Advertisements

Solution

Applying Gay-Lussac's law on the equation,

\[\ce{\underset{2 Vol.}{2C2H2_{(g)}} + \underset{5 Vol.}{5O2_{(g)}}-> \underset{4 Vol.}{4CO2_{(g)}} + 2H2O_{(g)}}\]

As 2 volumes of acetylene require = 5 volumes of oxygen

1 volume of acetylene require = `5/2` volumes of oxygen

∴ 200 cm3 of acetylene will require = `5/2 xx 200`

= 500 cmof oxygen

Further, 2 volumes of acetylene produce = 4 volumes of CO2

1 volume of acetylene produce = `4/2` volumes of CO2

∴ 200 cm3 of acetylene will produce = `4/2 xx 200`

= 400 cmof CO2
Hence, 500 cm3 of oxygen and 400 cm3 of carbon dioxide is formed.

shaalaa.com
  Is there an error in this question or solution?
Chapter 5: Mole Concept and Stoichiometry - Questions from ICSE Examinations [Page 117]

APPEARS IN

Frank Chemistry Part 2 [English] Class 10 ICSE
Chapter 5 Mole Concept and Stoichiometry
Questions from ICSE Examinations | Q 2009. 2. (a) | Page 117

RELATED QUESTIONS

Propane burns in air according to the following equation: 

C3H8 + 5O2 → 3CO2 + 4H2O

What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?


State Gay-Lussac’s law of combining volumes.


How does Avogadro's law explain Gay - lussac's law of combining volumes?


What volume of oxygen would be required for complete combustion of 100L of ethane according to the following equation?
2C2H6 + 7O2 → 4CO2 + 6H2O


Propane burns in air according to the following equation:

\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]

What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?


What volume of oxygen would be required to burn completely 400 ml of acetylene [C2H2]? Also calculate the volume of carbon dioxide formed.

\[\ce{2C2H2 + 5H2O -> 4CO2 + 2H2O(l)}\]


450 cm3 of nitrogen monoxide and 200 cm3 of oxygen are mixed together and ignited. Caclulate the composition of resulting mixture.

\[\ce{2NO + O2 → 2NO2}\]


LPG has 60% propane and 40% butane: 10 litres of this mixture is burnt. Calculate the volume of carbon dioxide added to atmosphere.

\[\ce{C3H8 + 5O2 → 3CO2 + 4H2O}\]

\[\ce{2C4H10 + 13O2 → 8CO2 + 10H2O}\]


The volumes of gases A, B, C and D are in the ratio, 1 : 2 : 2 : 4 under the same conditions of temperature and pressure.

  1. Which sample of gas contains the maximum number of molecules?
  2. If the temperature and pressure of gas A are kept constant, then what will happen to the volume of A when the number of molecules is doubled?
  3. If this ratio of gas volume refers to the reactants and products of a reaction, which gas law is being observed?
  4. If the volume of A is actually 5.6 dm3 at STP, calculate the number of molecules in the actual Volume of D at STP (Avogadro's number is 6 × 1023).
  5. Using your answer from (iv), state the mass of D if the gas is dinitrogen oxide (N2O).

112 cm3 of H2S(g) is mixed with 120 cm3 of Cl2(g) at STP to produce HCl(g) and sulphur(s). Calculate composition of the resulting mixture.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×