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112 cm3 of H2S(g) is mixed with 120 cm3 of Cl2(g) at STP to produce HCl(g) and sulphur(s). Calculate he volume of gaseous product formed.

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Question

112 cm3 of H2S(g) is mixed with 120 cm3 of Cl2(g) at STP to produce HCl(g) and sulphur(s). Calculate the volume of gaseous product formed.

Numerical
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Solution

Since 1 vol. Cl2 reacts with 1 vol. of H2S

∴ 112 cm3 Cl2 reacts with 112cm3 of H2S to produce 2 vol. of HCl i.e. 2(112) = 224 cm3

∴ product HCl produced is 224 cm3 and Cl2 (left unreacted) is 120 − 112 = 8 cm3

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Chapter 5: Mole concept and Stoichiometry - EXERCISE-5A [Page 75]

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S.P. Singh Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
EXERCISE-5A | Q 7. b. (i) | Page 75

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