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Question
A mixture of hydrogen and chlorine occupying 36 cm3 was exploded. On shaking it with water, 4 cm3 of hydrogen was left behind. Find the composition of the mixture.
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Solution
\[\ce{H2 + Cl2 -> 2HCl}\]
1 vol. : 1 vol. → 2 vol.
As 4 cm3 of hydrogen was left behind, hence, 36 − 4 = 32 cm3 of a mixture of hydrogen and chlorine exploded.
As, 1 Vol. of hydrogen requires 1 Vol. of chlorine
∴ 16 cm3 hydrogen requires 16 cm3 of chlorine
∴ Mixture is 20 cm3 (i.e., 16 + 4) of hydrogen and 16 cm3 of chlorine.
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