हिंदी

A mixture of hydrogen and chlorine occupying 36 cm3 was exploded. On shaking it with water, 4 cm3 of hydrogen was left behind. Find the composition of the mixture.

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प्रश्न

A mixture of hydrogen and chlorine occupying 36 cm3 was exploded. On shaking it with water, 4 cmof hydrogen was left behind. Find the composition of the mixture.

संख्यात्मक
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उत्तर

\[\ce{H2 + Cl2 -> 2HCl}\]

1 vol. : 1 vol. → 2 vol.

As 4 cm3 of hydrogen was left behind, hence, 36 − 4 = 32 cm3 of a mixture of hydrogen and chlorine exploded.

As, 1 Vol. of hydrogen requires 1 Vol. of chlorine

∴ 16 cm3 hydrogen requires 16 cm3 of chlorine

∴ Mixture is 20 cm3 (i.e., 16 + 4) of hydrogen and 16 cm3 of chlorine.

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अध्याय 5: Mole concept and Stoichiometry - EXERCISE-5A [पृष्ठ ७५]

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एस पी सिंग Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
EXERCISE-5A | Q 15. | पृष्ठ ७५

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