हिंदी

How Does Avogadro'S Law Explain Gay - Lussac'S Law of Combining Volumes?

Advertisements
Advertisements

प्रश्न

How does Avogadro's law explain Gay - lussac's law of combining volumes?

टिप्पणी लिखिए
Advertisements

उत्तर

Gay-Lussac experimentally determined that one volume of hydrogen and one volume of chlorine react to produce two volumes of hydrogen chloride gas.
According to Avogadro's law, if :
1 volume of hydrogen contains n molecules of the gas then 1 volume of chlorine also contains n molecules of the gas. Therefore 2 volume of hydrogen chloride contain 2n molecules of the gas.

\[\ce{H2 + Cl2 → 2HCI}\]
1 vol  1 vol       2 vol    (by Gay-Lussac)
n          n          2n        (By Avogadro)

but hydrogen and chlorine are diatomic.
So, 2 atoms + 2 atoms →  2 molecules
1 atom + 1 atom → 1 molecule
i.e. 1 molecule of hydrogen chloride is formed when 1 atom of hydrogen combines with 1 atom of chlorine. Thus Avogadro's law explains Gay-Lussac's law of combining volumes.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Mole Concept and Stoichiometry - Exercise 1 [पृष्ठ ११५]

APPEARS IN

फ्रैंक Chemistry Part 2 [English] Class 10 ICSE
अध्याय 5 Mole Concept and Stoichiometry
Exercise 1 | Q 7.2 | पृष्ठ ११५
एस पी सिंग Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
EXERCISE-5B | Q 3. (b) | पृष्ठ ८३

संबंधित प्रश्न

Water can split into hydrogen and oxygen under suitable conditions. The equations representing the change is:  2H2O(I) → 2H2 (g) + O2(g)
If a given experiment results in 2500cm3 of hydrogen being produced, what volume of oxygen is liberated at the same time under the same conditions of temperature and pressure?


What volume of oxygen would be required for complete combustion of 100L of ethane according to the following equation?
2C2H6 + 7O2 → 4CO2 + 6H2O


The reaction 4N2O + CH4 → CO2 + 2H2O + 4N2 takes place in the gaseous state. If the volumes of all the gases are measured at the same temperature, and pressure, calculate the volume of dinitrogen oxide (N2O), required to give 150cm3 of steam.


Propane burns in air according to the following equation:

\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]

What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?


1250 cc of oxygen was burnt with 300cc of ethane [C2H6]. Calculate the volume of carbon dioxide formed:

\[\ce{2C2H6 + 7O2  -> 4CO2 + 6H2O}\]


450 cm3 of nitrogen monoxide and 200 cm3 of oxygen are mixed together and ignited. Caclulate the composition of resulting mixture.

\[\ce{2NO + O2 → 2NO2}\]


112 cm3 of H2S(g) is mixed with 120 cm3 of Cl2(g) at STP to produce HCl(g) and sulphur(s). Write a balanced equation for this reaction and calculate

  1. the volume of gaseous product formed.
  2. composition of the resulting mixture.

The reaction: \[\ce{4N2O + CH4 -> CO2 + 2H2O + 4N2}\] takes place in the gaseous state. If all volumes are measured at the same temperature and pressure, calculate the volume of dinitrogen oxide (N2O) required to give 150 cm3 of steam.


1250 cc of oxygen was burnt with 300cc of ethane [C2H6]. Calculate the volume of unused oxygen formed:

\[\ce{2C2H6 + 7O2 -> 4CO2 + 6H2O}\]


Which amongst the following options is the correct graphical representation of Boyle’s law?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×