हिंदी

24 cc Marsh gas (CH4) was mixed with 106 cc oxygen and then exploded. On cooling the volume of the mixture became 82 cc, of which, 58 cc was unchanged oxygen. Which law does this experiment support?

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प्रश्न

24 cc Marsh gas (CH4) was mixed with 106 cc oxygen and then exploded. On cooling the volume of the mixture became 82 cc, of which, 58 cc was unchanged oxygen. Which law does this experiment support? Explain with calculations.

संख्यात्मक
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उत्तर

This experiment supports Gay Lussac’s law of combining volumes.

According to Gay lussac’s law, the volumes of gases reacting should be in a simple ratio.

\[\ce{CH4 + 2O2 → CO2 + 2H2O}\]

1V         2V            1V        0V

24 cc     48 cc        24 cc

1 vol. of CH4 requires O2 = 2 vols.

∴ 24 cc of CH4 requires O2 = 2 × 24 = 48 cc

Similarly, 24 cc of CH4 produce CO2 = 24 cc

∴ Vol. of O2 unused = 106 − 48 = 58cc

∴ Vol. of mixture on cooling = unused oxygen + CO2 formed

= 58 + 24 

= 82 cc

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Mole concept and Stoichiometry - EXERCISE-5A [पृष्ठ ७५]

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एस पी सिंग Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
EXERCISE-5A | Q 5. | पृष्ठ ७५

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