हिंदी

112 cm3 of H2S(g) is mixed with 120 cm3 of Cl2(g) at STP to produce HCl(g) and sulphur(s). Calculate he volume of gaseous product formed.

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प्रश्न

112 cm3 of H2S(g) is mixed with 120 cm3 of Cl2(g) at STP to produce HCl(g) and sulphur(s). Calculate the volume of gaseous product formed.

संख्यात्मक
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उत्तर

Since 1 vol. Cl2 reacts with 1 vol. of H2S

∴ 112 cm3 Cl2 reacts with 112cm3 of H2S to produce 2 vol. of HCl i.e. 2(112) = 224 cm3

∴ product HCl produced is 224 cm3 and Cl2 (left unreacted) is 120 − 112 = 8 cm3

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अध्याय 5: Mole concept and Stoichiometry - EXERCISE-5A [पृष्ठ ७५]

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एस पी सिंग Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
EXERCISE-5A | Q 7. b. (i) | पृष्ठ ७५

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112 cm3 of H2S(g) is mixed with 120 cm3 of Cl2(g) at STP to produce HCl(g) and sulphur(s). Write a balanced equation for this reaction and calculate

  1. the volume of gaseous product formed.
  2. composition of the resulting mixture.

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  1. Which sample of gas contains the maximum number of molecules?
  2. If the temperature and pressure of gas A are kept constant, then what will happen to the volume of A when the number of molecules is doubled?
  3. If this ratio of gas volume refers to the reactants and products of a reaction, which gas law is being observed?
  4. If the volume of A is actually 5.6 dm3 at STP, calculate the number of molecules in the actual Volume of D at STP (Avogadro's number is 6 × 1023).
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