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If 6 Liters of Hydrogen and 4 Liters of Chlorine Are Mixed and Exploded and If Water is Added to the Gases Formed, Find the Volume of the Residual Gas.

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प्रश्न

If 6 liters of hydrogen and 4 liters of chlorine are mixed and exploded and if water is added to the gases formed, find the volume of the residual gas.

संक्षेप में उत्तर
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उत्तर १

  1. 6 litres of hydrogen and 4 litres of chlorine when mixed, results in the formation of 8 litres ofHCl gas.
  2. When water is added to it, it results in the formation of hydrochloric acid. Chlorine acts as a limiting agent leving behind only 2 litres of hydrogen gas.

 iii. Therefore, the volume of the residual gas will be 2 litres.

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उत्तर २

\[\ce{H2 + Cl2 -> 2HCl}\]
1 vol. 1 vol.      2 vol.
1 lit.   1 lit.        2 lit.

1 lit. of H2 can use 1 lit. of Cl2

∴ 4 lit. of H2 can be combined with 4 lit. of Cl2

\[\ce{H2 + Cl2 -> 2HCl}\]
6 lit.   4 lit.

1 lit of H2 + 1 lit of Cl2 = 2 lit of HCl

4 lit of H2 forms 2 x 4 = 8 lit HCl

Hence after reaction 8 lit of HCl + 2 lit of H2 i.e. 10 lit

When water is added to the gases formed HCl dissolves and residual gas is 2 lit. H2·

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अध्याय 5: Mole concept and Stoichiometry - EXERCISE-5A [पृष्ठ ७५]

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एस पी सिंग Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
EXERCISE-5A | Q 13. | पृष्ठ ७५

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State Gay-Lussac's law of combining volumes.


The reaction 4N2O + CH4 → CO2 + 2H2O + 4N2 takes place in the gaseous state. If the volumes of all the gases are measured at the same temperature, and pressure, calculate the volume of dinitrogen oxide (N2O), required to give 150cm3 of steam.


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\[\ce{2C2H2_{(g)} + 5O2_{(g)}-> 4CO2_{(g)} + 2H2O_{(g)}}\]


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\[\ce{2C2H6 + 7O2  -> 4CO2 + 6H2O}\]


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\[\ce{2NO + O2 → 2NO2}\]


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\[\ce{4NH3 + 5O2 → 4NO + 6H2O}\]

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