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प्रश्न
What volume of propane is burnt for every 500 cm3 of air used in the reaction under the same conditions? (assuming oxygen is `1/5`th of air)
\[\ce{C3H8 + 5O2 → 3CO2 + 4H2O}\]
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उत्तर
Volume of O2 in 500 cm3 of air = 20%
= `20/100 xx 500`
= 100 cm3
\[\ce{C3H8 + 5O2 → 3CO2 + 4H2O}\]
1 vol. 5 vol.
∴ Volume of propane burnt = `100/5`
= 20 cm3
संबंधित प्रश्न
Propane burns in air according to the following equation:
C3H8 + 5O2 → 3CO2 + 4H2O
What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?
State Gay-Lussac's law of combining volumes.
How does Avogadro's law explain Gay - lussac's law of combining volumes?
When gases react their volumes bear a simple ratio to each other, under the same conditions of temperature and pressure. Who proposed this gas law?
Propane burns in air according to the following equation:
\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]
What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?
What volume of oxygen would be required to burn completely 400 ml of acetylene [C2H2]? Also calculate the volume of carbon dioxide formed.
\[\ce{2C2H2 + 5H2O -> 4CO2 + 2H2O(l)}\]
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\[\ce{4NH3 + 5O2 → 4NO + 6H2O}\]
If 27 litres of reactants are consumed, what volume of nitrogen monoxide is produced at the same temperature and pressure?
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