हिंदी

What volume of propane is burnt for every 500 cm3 of air used in the reaction under the same conditions? (assuming oxygen is 15th of air) CA3HA8+5OA2⟶3COA2+4HA2O - Chemistry

Advertisements
Advertisements

प्रश्न

What volume of propane is burnt for every 500 cm3 of air used in the reaction under the same conditions? (assuming oxygen is `1/5`th of air)

\[\ce{C3H8 + 5O2 → 3CO2 + 4H2O}\]

संख्यात्मक
Advertisements

उत्तर

Volume of O2 in 500 cm3 of air = 20%

= `20/100 xx 500`

= 100 cm3

\[\ce{C3H8 + 5O2 → 3CO2 + 4H2O}\]
1 vol.      5 vol.

∴ Volume of propane burnt = `100/5`

= 20 cm3

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

संबंधित प्रश्न

Propane burns in air according to the following equation: 

C3H8 + 5O2 → 3CO2 + 4H2O

What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?


Water can split into hydrogen and oxygen under suitable conditions. The equations representing the change is:  2H2O(I) → 2H2 (g) + O2(g)
If a given experiment results in 2500cm3 of hydrogen being produced, what volume of oxygen is liberated at the same time under the same conditions of temperature and pressure?


24 cc Marsh gas (CH4) was mixed with 106 cc oxygen and then exploded. On cooling the volume of the mixture became 82 cc, of which, 58 cc was unchanged oxygen. Which law does this experiment support? Explain with calculations.


What volume of oxygen would be required to burn completely 400 ml of acetylene [C2H2]? Also calculate the volume of carbon dioxide formed.

\[\ce{2C2H2 + 5H2O -> 4CO2 + 2H2O(l)}\]


Ammonia may be oxidised to nitrogen monoxide in the presence of a catalyst according to the following equation.

\[\ce{4NH3 + 5O2 → 4NO + 6H2O}\]

If 27 litres of reactants are consumed, what volume of nitrogen monoxide is produced at the same temperature and pressure?


A mixture of hydrogen and chlorine occupying 36 cm3 was exploded. On shaking it with water, 4 cmof hydrogen was left behind. Find the composition of the mixture.


200 cm3 of CO2 is collected at STP when a mixture of acetylene and oxygen is ignited. Calculate the volume of acetylene and oxygen at STP. in original mixture.

\[\ce{2C2H2_{(g)} + 5O2_{(g)} → 4CO2_{(g)} + 2H2O_{(g)}}\]


The reaction: \[\ce{4N2O + CH4 -> CO2 + 2H2O + 4N2}\] takes place in the gaseous state. If all volumes are measured at the same temperature and pressure, calculate the volume of dinitrogen oxide (N2O) required to give 150 cm3 of steam.


The volumes of gases A, B, C and D are in the ratio, 1 : 2 : 2 : 4 under the same conditions of temperature and pressure.

  1. Which sample of gas contains the maximum number of molecules?
  2. If the temperature and pressure of gas A are kept constant, then what will happen to the volume of A when the number of molecules is doubled?
  3. If this ratio of gas volume refers to the reactants and products of a reaction, which gas law is being observed?
  4. If the volume of A is actually 5.6 dm3 at STP, calculate the number of molecules in the actual Volume of D at STP (Avogadro's number is 6 × 1023).
  5. Using your answer from (iv), state the mass of D if the gas is dinitrogen oxide (N2O).

1250 cc of oxygen was burnt with 300cc of ethane [C2H6]. Calculate the volume of unused oxygen formed:

\[\ce{2C2H6 + 7O2 -> 4CO2 + 6H2O}\]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×