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Question
What volume of propane is burnt for every 500 cm3 of air used in the reaction under the same conditions? (assuming oxygen is `1/5`th of air)
\[\ce{C3H8 + 5O2 → 3CO2 + 4H2O}\]
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Solution
Volume of O2 in 500 cm3 of air = 20%
= `20/100 xx 500`
= 100 cm3
\[\ce{C3H8 + 5O2 → 3CO2 + 4H2O}\]
1 vol. 5 vol.
∴ Volume of propane burnt = `100/5`
= 20 cm3
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