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24 cc Marsh gas (CH4) was mixed with 106 cc oxygen and then exploded. On cooling the volume of the mixture became 82 cc, of which, 58 cc was unchanged oxygen. Which law does this experiment support?

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Question

24 cc Marsh gas (CH4) was mixed with 106 cc oxygen and then exploded. On cooling the volume of the mixture became 82 cc, of which, 58 cc was unchanged oxygen. Which law does this experiment support? Explain with calculations.

Numerical
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Solution

This experiment supports Gay Lussac’s law of combining volumes.

According to Gay lussac’s law, the volumes of gases reacting should be in a simple ratio.

\[\ce{CH4 + 2O2 → CO2 + 2H2O}\]

1V         2V            1V        0V

24 cc     48 cc        24 cc

1 vol. of CH4 requires O2 = 2 vols.

∴ 24 cc of CH4 requires O2 = 2 × 24 = 48 cc

Similarly, 24 cc of CH4 produce CO2 = 24 cc

∴ Vol. of O2 unused = 106 − 48 = 58cc

∴ Vol. of mixture on cooling = unused oxygen + CO2 formed

= 58 + 24 

= 82 cc

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Chapter 5: Mole concept and Stoichiometry - EXERCISE-5A [Page 75]

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S.P. Singh Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
EXERCISE-5A | Q 5. | Page 75

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