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प्रश्न
LPG has 60% propane and 40% butane: 10 litres of this mixture is burnt. Calculate the volume of carbon dioxide added to atmosphere.
\[\ce{C3H8 + 5O2 → 3CO2 + 4H2O}\]
\[\ce{2C4H10 + 13O2 → 8CO2 + 10H2O}\]
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उत्तर
Ratio of propane and Butane in mixture
= 60 : 40
= 3 : 2
Ratio in 10 litres mixture = `3/5 xx 10 and 2/5 xx 10`
= 6 lit : 4 lit
\[\ce{C3H8 + 5O2 → 3CO2 + 4H2O}\]
1 vol 3 vol
1 volume of propane produces CO2 = 3 volumes
∴ 6 litres produces CO2 = 3 x 6
= 18 litres ...(i)
\[\ce{2C4H10 + 13O2 → 8CO2 + 10H2O}\]
2 vol 8 vol
2 litres of Butane produces CO2 = 8 litres
∴ 4 litres produce CO2 = `(8 xx 4)/2`
= 16 litres ...(ii)
∴ CO2 added to atmosphere = 18 + 16
= 34 litres.
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What volume of oxygen would be required for complete combustion of 100L of ethane according to the following equation?
2C2H6 + 7O2 → 4CO2 + 6H2O
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\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]
What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?
What volume of oxygen would be required to burn completely 400 ml of acetylene [C2H2]? Also calculate the volume of carbon dioxide formed.
\[\ce{2C2H2 + 5H2O -> 4CO2 + 2H2O(l)}\]
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\[\ce{2C2H6 + 7O2 -> 4CO2 + 6H2O}\]
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\[\ce{C3H8 + 5O2 → 3CO2 + 4H2O}\]
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\[\ce{4NH3 + 5O2 → 4NO + 6H2O}\]
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\[\ce{2C2H2_{(g)} + 5O2_{(g)} → 4CO2_{(g)} + 2H2O_{(g)}}\]
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