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Ammonia May Be Oxidised to Nitrogen Monoxide in the Presence of a Catalyst According to the Following Equation. 4nh3 + 5o2 → 4no + 6h2o If 27 Litres of Reactants Are Consumed, What Volume of Nitro

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Question

Ammonia may be oxidised to nitrogen monoxide in the presence of a catalyst according to the following equation.

\[\ce{4NH3 + 5O2 → 4NO + 6H2O}\]

If 27 litres of reactants are consumed, what volume of nitrogen monoxide is produced at the same temperature and pressure?

Numerical
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Solution

\[\ce{4NH3 + 5O2 → 4NO + 6H2O}\]
4 V          5 V            4 V   

9 litres of reactants gives 4 litres of NO

So, 27 litres of reactants will give = `27 × 4/9` = 12 litres of NO

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Chapter 5: Mole concept and Stoichiometry - EXERCISE-5A [Page 75]

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S.P. Singh Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
EXERCISE-5A | Q 14. | Page 75

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