मराठी

Ammonia May Be Oxidised to Nitrogen Monoxide in the Presence of a Catalyst According to the Following Equation. 4nh3 + 5o2 → 4no + 6h2o If 27 Litres of Reactants Are Consumed, What Volume of Nitro

Advertisements
Advertisements

प्रश्न

Ammonia may be oxidised to nitrogen monoxide in the presence of a catalyst according to the following equation.

\[\ce{4NH3 + 5O2 → 4NO + 6H2O}\]

If 27 litres of reactants are consumed, what volume of nitrogen monoxide is produced at the same temperature and pressure?

संख्यात्मक
Advertisements

उत्तर

\[\ce{4NH3 + 5O2 → 4NO + 6H2O}\]
4 V          5 V            4 V   

9 litres of reactants gives 4 litres of NO

So, 27 litres of reactants will give = `27 × 4/9` = 12 litres of NO

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Mole concept and Stoichiometry - EXERCISE-5A [पृष्ठ ८१]

APPEARS IN

एस.पी. सिंह Concise Chemistry [English] Class 10 ICSE
पाठ 5 Mole concept and Stoichiometry
EXERCISE-5A | Q 11. | पृष्ठ ८१

संबंधित प्रश्‍न

Water can split into hydrogen and oxygen under suitable conditions. The equations representing the change is:  2H2O(I) → 2H2 (g) + O2(g)
If a given experiment results in 2500cm3 of hydrogen being produced, what volume of oxygen is liberated at the same time under the same conditions of temperature and pressure?


The reaction 4N2O + CH4 → CO2 + 2H2O + 4N2 takes place in the gaseous state. If the volumes of all the gases are measured at the same temperature, and pressure, calculate the volume of dinitrogen oxide (N2O), required to give 150cm3 of steam.


Propane burns in air according to the following equation:

\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]

What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?


450 cm3 of nitrogen monoxide and 200 cm3 of oxygen are mixed together and ignited. Caclulate the composition of resulting mixture.

\[\ce{2NO + O2 → 2NO2}\]


A mixture of hydrogen and chlorine occupying 36 cm3 was exploded. On shaking it with water, 4 cm3 of hydrogen was left behind. Find the composition of the mixture.


LPG has 60% propane and 40% butane: 10 litres of this mixture is burnt. Calculate the volume of carbon dioxide added to atmosphere.

\[\ce{C3H8 + 5O2 → 3CO2 + 4H2O}\]

\[\ce{2C4H10 + 13O2 → 8CO2 + 10H2O}\]


The volumes of gases A, B, C and D are in the ratio, 1 : 2 : 2 : 4 under the same conditions of temperature and pressure.

  1. Which sample of gas contains the maximum number of molecules?
  2. If the temperature and pressure of gas A are kept constant, then what will happen to the volume of A when the number of molecules is doubled?
  3. If this ratio of gas volume refers to the reactants and products of a reaction, which gas law is being observed?
  4. If the volume of A is actually 5.6 dm3 at STP, calculate the number of molecules in the actual Volume of D at STP (Avogadro's number is 6 × 1023).
  5. Using your answer from (iv), state the mass of D if the gas is dinitrogen oxide (N2O).

112 cm3 of H2S(g) is mixed with 120 cm3 of Cl2(g) at STP to produce HCl(g) and sulphur(s). Calculate the volume of gaseous product formed.


112 cm3 of H2S(g) is mixed with 120 cm3 of Cl2(g) at STP to produce HCl(g) and sulphur(s). Calculate composition of the resulting mixture.


Which amongst the following options is the correct graphical representation of Boyle’s law?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×