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Calcium carbide is used for the artificial ripening of fruits. Actually the fruit ripens because of the heat evolved while calcium carbide reacts with the moisture. - Chemistry

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प्रश्न

Calcium carbide is used for the artificial ripening of fruits. Actually the fruit ripens because of the heat evolved while calcium carbide reacts with the moisture. During this reaction calcium hydroxide and acetylene gas are formed. If 200 cm3 of acetylene is formed from a certain mass of calcium carbide, find the volume of oxygen required and carbon dioxide formed during the complete combustion. The combustion reaction can be represented as below.

\[\ce{2C2H2_{(g)} + 5O2_{(g)}-> 4CO2_{(g)} + 2H2O_{(g)}}\]

संख्यात्मक
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उत्तर

Applying Gay-Lussac's law on the equation,

\[\ce{\underset{2 Vol.}{2C2H2_{(g)}} + \underset{5 Vol.}{5O2_{(g)}}-> \underset{4 Vol.}{4CO2_{(g)}} + 2H2O_{(g)}}\]

As 2 volumes of acetylene require = 5 volumes of oxygen

1 volume of acetylene require = `5/2` volumes of oxygen

∴ 200 cm3 of acetylene will require = `5/2 xx 200`

= 500 cmof oxygen

Further, 2 volumes of acetylene produce = 4 volumes of CO2

1 volume of acetylene produce = `4/2` volumes of CO2

∴ 200 cm3 of acetylene will produce = `4/2 xx 200`

= 400 cmof CO2
Hence, 500 cm3 of oxygen and 400 cm3 of carbon dioxide is formed.

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पाठ 5: Mole Concept And Stoichiometry - Exercise 9 [पृष्ठ १२३]

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फ्रँक Chemistry Part 2 [English] Class 10 ICSE
पाठ 5 Mole Concept And Stoichiometry
Exercise 9 | Q 2.1 | पृष्ठ १२३

संबंधित प्रश्‍न

State Gay-Lussac's law of combining volumes.


Water can split into hydrogen and oxygen under suitable conditions. The equations representing the change is:  2H2O(I) → 2H2 (g) + O2(g)
If a given experiment results in 2500cm3 of hydrogen being produced, what volume of oxygen is liberated at the same time under the same conditions of temperature and pressure?


What volume of oxygen would be required for complete combustion of 100L of ethane according to the following equation?
2C2H6 + 7O2 → 4CO2 + 6H2O


Propane burns in air according to the following equation:

\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]

What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?


If 6 liters of hydrogen and 4 liters of chlorine are mixed and exploded and if water is added to the gases formed, find the volume of the residual gas.


Ammonia may be oxidised to nitrogen monoxide in the presence of a catalyst according to the following equation.

\[\ce{4NH3 + 5O2 → 4NO + 6H2O}\]

If 27 litres of reactants are consumed, what volume of nitrogen monoxide is produced at the same temperature and pressure?


A mixture of hydrogen and chlorine occupying 36 cm3 was exploded. On shaking it with water, 4 cmof hydrogen was left behind. Find the composition of the mixture.


200 cm3 of CO2 is collected at STP when a mixture of acetylene and oxygen is ignited. Calculate the volume of acetylene and oxygen at STP. in original mixture.

\[\ce{2C2H2_{(g)} + 5O2_{(g)} → 4CO2_{(g)} + 2H2O_{(g)}}\]


The reaction: \[\ce{4N2O + CH4 -> CO2 + 2H2O + 4N2}\] takes place in the gaseous state. If all volumes are measured at the same temperature and pressure, calculate the volume of dinitrogen oxide (N2O) required to give 150 cm3 of steam.


The volumes of gases A, B, C and D are in the ratio, 1 : 2 : 2 : 4 under the same conditions of temperature and pressure.

  1. Which sample of gas contains the maximum number of molecules?
  2. If the temperature and pressure of gas A are kept constant, then what will happen to the volume of A when the number of molecules is doubled?
  3. If this ratio of gas volume refers to the reactants and products of a reaction, which gas law is being observed?
  4. If the volume of A is actually 5.6 dm3 at STP, calculate the number of molecules in the actual Volume of D at STP (Avogadro's number is 6 × 1023).
  5. Using your answer from (iv), state the mass of D if the gas is dinitrogen oxide (N2O).

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