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प्रश्न
1250 cc of oxygen was burnt with 300cc of ethane [C2H6]. Calculate the volume of carbon dioxide formed:
\[\ce{2C2H6 + 7O2 -> 4CO2 + 6H2O}\]
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उत्तर
\[\ce{2C2H6 + 7O2 -> 4CO2 + 6H2O}\]
2 vol 7 vol
300 cc
2 vol. of ethane forms 4 volumes of carbon dioxide
1 vol. of ethane forms `4/2` volumes of carbon dioxide.
300 cc will form `4/2 xx 300`
= 600 cc of CO2.
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\[\ce{2C2H6 + 7O2 -> 4CO2 + 6H2O}\]
