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1250 cc of oxygen was burnt with 300cc of ethane [C2H6]. Calculate the volume of carbon dioxide formed: 2CA2HA6+7OA2⟶4COA2+6HA2O - Chemistry

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Question

1250 cc of oxygen was burnt with 300cc of ethane [C2H6]. Calculate the volume of carbon dioxide formed:

\[\ce{2C2H6 + 7O2  -> 4CO2 + 6H2O}\]

Numerical
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Solution

\[\ce{2C2H6 + 7O2  -> 4CO2 + 6H2O}\]
2 vol         7 vol
300 cc

2 vol. of ethane forms 4 volumes of carbon dioxide

1 vol. of ethane forms `4/2` volumes of carbon dioxide.

300 cc will form `4/2 xx 300`

= 600 cc of CO2.

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1250 cc of oxygen was burnt with 300cc of ethane [C2H6]. Calculate the volume of unused oxygen formed:

\[\ce{2C2H6 + 7O2 -> 4CO2 + 6H2O}\]


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