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Question
1250 cc of oxygen was burnt with 300cc of ethane [C2H6]. Calculate the volume of unused oxygen formed:
\[\ce{2C2H6 + 7O2 -> 4CO2 + 6H2O}\]
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Solution
\[\ce{2C2H6 + 7O2 -> 4CO2 + 6H2O}\]
2 vol 7 vol
300 cc
2 vol. of ethane requires 7 volumes of oxygen
2 vol. of ethane requires `7/2` volumes of oxygen
300 cc of ethane requires `7/2 xx 300` = 1050 cc
Total volume of oxygen = 1250 cc
Volume of oxygen used = 1050 cc
Unused oxygen = (1250 − 1050) cc
= 200 cc.
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