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1250 cc of oxygen was burnt with 300cc of ethane [C2H6]. Calculate the volume of unused oxygen formed: 2CA2HA6+7OA2⟶4COA2+6HA2O

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Question

1250 cc of oxygen was burnt with 300cc of ethane [C2H6]. Calculate the volume of unused oxygen formed:

\[\ce{2C2H6 + 7O2 -> 4CO2 + 6H2O}\]

Numerical
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Solution

\[\ce{2C2H6 + 7O2  -> 4CO2 + 6H2O}\]
2 vol         7 vol
300 cc

2 vol. of ethane requires 7 volumes of oxygen

2 vol. of ethane requires `7/2` volumes of oxygen

300 cc of ethane requires `7/2 xx 300` = 1050 cc

Total volume of oxygen = 1250 cc

Volume of oxygen used = 1050 cc

Unused oxygen = (1250 − 1050) cc

= 200 cc.

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Chapter 5: Mole concept and Stoichiometry - EXERCISE-5A [Page 75]

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S.P. Singh Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
EXERCISE-5A | Q 8. (i) | Page 75

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