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Question
Water can split into hydrogen and oxygen under suitable conditions. The equations representing the change is: 2H2O(I) → 2H2 (g) + O2(g)
If a given experiment results in 2500cm3 of hydrogen being produced, what volume of oxygen is liberated at the same time under the same conditions of temperature and pressure?
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Solution
Given equation is: 2H2O (I) → 2H2 (g) + O2 (g)
According to Gay-Lussac's law;
2 volume of water produces 2 volume of hydrogen and 1 volume of oxygen
i.e 2 volume of water produces = 2 volume of hydrogen
= 2500cm3
2 volume of water will produce =1 volume of Oxygen
= 2500/ 2 = 1250 cm3
i.e.= 1250 cm3
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