मराठी

What volume of air (containing 20% O2 by volume) will be required to burn completely 10 cm3 of methane? CHA4+2OA2⟶COA2+2HA2O 2CA2HA2+5OA2⟶4COA2+2HA2O

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प्रश्न

What volume of air (containing 20% O2 by volume) will be required to burn completely 10 cm3 of methane and acetylene?

\[\ce{CH4 + 2O2 → CO2 + 2H2O}\]

\[\ce{2C2H2 + 5O2 -> 4CO2 + 2H2O}\]

संख्यात्मक
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उत्तर

Methane + Oxygen

\[\ce{\underset{10 cm^3}{\underset{1 V}{CH4} + \underset{2 V}{2O2}} -> CO2 + 2H2O}\]

∴ Volume of \[\ce{O2}\] required = 10 × 2 = 20 cm3

∴ Volume of air = 20 × 5 = 100 cm3

∴ 20 cc of \[\ce{O2}\] is contained in 100 cm3 of air.

Acetylene + Oxygen

\[\ce{\underset{10 cm^3}{\underset{2 V}{2C2H2} + \underset{5 V}{5O2}} -> 4CO2 + 2H2O}\]

∴ Volume of \[\ce{O2}\] required = `5/2 xx 10 = 25` cm3

Total O2 needed = 20 + 25

= 45 cm3

Air conrains 20% oxygen,

∴ Air volume = `45/0.20`

= 225 cm3

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पाठ 5: Mole concept and Stoichiometry - EXERCISE-5A [पृष्ठ ७५]

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एस.पी. सिंह Concise Chemistry [English] Class 10 ICSE
पाठ 5 Mole concept and Stoichiometry
EXERCISE-5A | Q 16. (i) | पृष्ठ ७५

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