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Answer the following: Find the real numbers x and y such that x1+2i+y3+2i=5+6i-1+8i

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Question

Answer the following:

Find the real numbers x and y such that `x/(1 + 2"i") + y/(3 + 2"i") = (5 + 6"i")/(-1 + 8"i")`

Sum
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Solution

`x/(1 + 2"i") + y/(3 + 2"i") = (5 + 6"i")/(-1 + 8"i")`

∴ `((3 + 2"i")x + (1 + 2"i")y)/((1 + 2"i")(3 + 2"i")) = (5 + 6"i")/(-1 + 8"i")`

∴ `((3 + 2"i")x + (1 + 2"i")y)/(3 + 2"i" + 6"i" + 4"i"^2) = (5 + 6"i")/(-1 + 8"i")`

∴ `((3 + 2"i")x + (1 + 2"i")y)/(3 + 8"i" - 4) = (5 + 6"i")/(-1 + 8"i")`   ...[∵ i2 = – 1]

∴ `(3x + 2"i"x + y + 2"i"y)/(-1 + 8"i") = (5 + 6"i")/(-1 + 8"i")`

∴ (3x + y) + (2x + 2y)i = 5 + 6i

Equating the real and imaginary parts separately, we get,

3x + y = 5     ...(1)

and 2x + 2y = 6

i.e., x + y = 3   ...(2)

On subtracting, we get,

2x = 2

∴ x = 1

∴ from (2), 1 + y = 3

∴ y = 2

Hence, x = 1, y = 2.

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Chapter 1: Complex Numbers - Miscellaneous Exercise 1.2 [Page 22]

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