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Question
Answer in brief.
Give a simple chemical test to distinguish between ethanol and ethyl bromide.
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Solution
i. Ethanol on reaction with a very strong base like alkali metal Na or K gives sodium or potassium ethoxide with the liberation of hydrogen gas.
\[\ce{2CH3CH2 - OH + 2Na -> 2CH3CH2O^-Na+ + H2_{(g)}↑}\]
ii. Ethyl bromide on reaction with sodium metal does not liberate hydrogen gas.
\[\ce{2CH3CH2Br + 2Na -> CH3CH2 - CH2CH3 + 2NaBr}\]
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