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Question
A compound X, of boron reacts with NH3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF3 with Lithium aluminium hydride. The compounds X and Y are represented by the formulas.
Options
B2H6, B3N3H6
B2O3, B3N3H6
BF3, B3N3H6
B3N3H6, B2H6
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Solution
B2H6, B3N3H6
Explanation:
A compound X, of boron, reacts with NH3 on heating to give another compound YY which is called inorganic benzene.
\[\ce{\underset{X(Diborance)}{3H2H6} + 6NH3 -> 3[BH2(NH3)2]+ [BH4]- ->[heat] \underset{Y(Borazole Inorganic Benzene)}{2B3N3H6} + 12H2}\]
\[\ce{4BF3 + 3LiAlH4 -> \underset{X}{2B2H6} + 3LiF + 3AlF3}\]
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