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A compound X, of boron reacts with NH3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF3 with Lithium aluminium hydride.

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प्रश्न

A compound X, of boron reacts with NH3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF3 with Lithium aluminium hydride. The compounds X and Y are represented by the formulas.

पर्याय

  • B2H6, B3N3H6

  • B2O3, B3N3H6

  • BF3, B3N3H6

  • B3N3H6, B2H6

MCQ
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उत्तर

B2H6, B3N3H6 

Explanation:

A compound X, of boron, reacts with NH3 on heating to give another compound YY which is called inorganic benzene.

\[\ce{\underset{X(Diborance)}{3H2H6} + 6NH3 -> 3[BH2(NH3)2]+ [BH4]- ->[heat] \underset{Y(Borazole Inorganic Benzene)}{2B3N3H6} + 12H2}\]

\[\ce{4BF3 + 3LiAlH4 -> \underset{X}{2B2H6} + 3LiF + 3AlF3}\]

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पाठ 11: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १३६]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
पाठ 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 11 | पृष्ठ १३६

संबंधित प्रश्‍न

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PbX2 is more stable than PbX4.


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\[\ce{Z + 3 LiAlH4 -> X + 3LiF + 3AlF_3}\]

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Column I Column II
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Column I Column II
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