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Match the species given in Column I with the properties mentioned in Column II. Column I Column II (i) BFX4− (a) Oxidation state of central atom is +4 (ii) AICI3 (b) Strong oxidising agent - Chemistry

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प्रश्न

Match the species given in Column I with the properties mentioned in Column II.

Column I Column II
(i) \[\ce{BF^{-}4}\] (a) Oxidation state of central atom is +4
(ii) AICI3 (b) Strong oxidising agent
(iii) SnO (c) Lewis acid
(iv) PbO2 (d) Can be further oxidised
  (e) Tetrahedral shape
जोड्या लावा/जोड्या जुळवा
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उत्तर

Column I Column II
(i) \[\ce{BF^{-}4}\] (e) Tetrahedral shape
(ii) AICI3 (c) Lewis acid
(iii) SnO (d) Can be further oxidised
(iv) PbO2 (b) Strong oxidising agent

Explanation:

(i) \[\ce{BF^{-}4}\]: Tetrahedral shape, sp3 hybridisation, regular geometry.

(ii) AlCl3: Octet of Al not complete, acts as Lewis acid.

(iii) SnO: Sn2+ can show +4 oxidation state.

(iv) PbO2: Due to inert pair effect, Pb4+ is less stable than Pb2+ and hence acts as strong oxidising agent.

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Group 13 Elements - The Boron Family
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पाठ 11: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १३९]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
पाठ 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 36 | पृष्ठ १३९

संबंधित प्रश्‍न

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(i) The two birdged hydrogen atoms and the two boron atoms lie in one plane;

(ii) Out of six B – H bonds two bonds can be described in terms of 3 centre 2-electron bonds.

(iii) Out of six B – H bonds four B – H bonds can be described in terms of 3 centre 2 electron bonds;

(iv) The four-terminal B – H bonds are two centre-two electron regular bonds.


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\[\ce{X + 6H2 -> Y + 6H2}\]

\[\ce{3X + 3O2 ->[Δ] B2O3 + 3H2O}\]


Match the species given in Column I with the hybridisation given in Column II.

Column I Column II
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(iii) Boron in B2H6 (c) sp3d2
(iv) Carbon in Buckminsterfullerene  
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(vi) Germanium in [GeCl6]2–  

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Which one of the following is the correct statement?


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