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Chapters
2: Compound Interest
3: Expansions
4: Factorisation
5: Simultaneous Linear Equations
6: Indices/Exponents
7: Logarithms
8: Triangles
9: Mid-point Theorem
10: Pythagoras Theorem
11: Rectilinear Figures
12: Constructions of Polygons
▶ 13: Theorems on Area
14: Circles
15: Statistics
16: Mensuration
17: Trigonometric Ratios
18: Trigonometric Ratios of Some Standard Angles and Complementary Angles
Chapter 19: Co-ordinate Geometry: An Introduction
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Solutions for Chapter 13: Theorems on Area
Below listed, you can find solutions for Chapter 13 of CISCE Nootan for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई.
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई 13 Theorems on Area Exercise 13A [Pages 256 - 260]
In the adjoining figure; if the area of parallelogram ABCD is 90 cm2, find :
- area of parallelogram ABEF.
- area of ΔABE.

In the adjoining figure; AB = 16 cm, DM = 4 cm and BC = 8 cm. Find the length of DN.

In the adjoining figure, BD = 2CD. If area of ΔABC = 36 cm2, find the area of ΔABD.

In the adjoining figure, ABCD is a rectangle in which AB = 10 cm, AD = 6 cm. If AP || BQ, find :
- ar (|| gm ABQP)
- ar (ΔАВР)

The area of a parallelogram is 150 cm2. The ratio of its base and corresponding altitude is 3 : 2. Find the base and corresponding altitude.
In the adjoining figure; AN = NB and DM = MC in the parallelogram ABCD. If area (ABCD) = 44 cm2,
- find the area of ΔВСЕ.
- find the area of parallelogram BNMC.

In the adjoining figure; ABCD is a parallelogram. If AP = BP and CP meets the diagonal BD at Q and area of ΔBPQ = 20 cm2, find:
- PQ : QC.
- Area of ΔPBC.
- Area of parallelogram ABCD.

In the adjoining figure; ABCD is a parallelogram whose area is 324 cm2. If P is a point on AB such that AP : PB = 1 : 2, find:
- Area of ΔAPD.
- QP : QD.

In a parallelogram ABCD, P is a point on DC such that DP : PC = 2 : 3. If area of ΔDPB = 40 cm2, find the area of ◻ABCD.

In the adjoining figure; BD = DC and AE = ED. Prove that area of ΔACE = `1/4` × area of ΔАВС.

In the adjoining figure, D is the mid-point of BC and E be any point on AD.
Prove that :
- area (ΔEBD) = area (ΔECD).
- area (ΔABE) = area (ΔACE).

In a parallelogram ABCD, M and N are the points on AB and BC respectively.
Prove that:
- ΔCMD and ΔAND are equal in area.
- area (ΔAND) = area (ΔAMD) + area (ΔCMB).
In a trapezium ABCD, AB || DC and the diagonals AC and BD intersect at point ‘O’. Prove that area (ΔАOD) = area (ΔBОС).
In the adjoining figure, O is the mid-point of diagonal AC of a quadrilateral ABCD. Prove that area (◻ABOD) = area (◻BODC).

In the adjoining figure, AD = BD and ◻BDEC is a parallelogram. Prove that area (ΔABC) = area (◻BDEC).

In the adjoining figure, PQ || BC.
Prove that :
- area (ΔABQ) = area (ΔАСР).
- area (ΔΒΟP) = area (ΔCOQ).

In the adjoining figure, ABCD is a parallelogram. A line through A intersects DC at P and meets BC produced at Q.
Prove that : area (ΔBCP) = area (ΔDPQ).

In the adjoining figure, D is the mid-point of AB. P is any point on BC and CQ || PD meets AB at Q.
Prove that : area (ΔBPQ) = `1/2` × area (ΔABC)

In a trapezium ABCD, AB || DC. A line parallel to AC cuts AB at P and BC at Q. Prove that area (ΔАPD) = area (ΔACQ).
In the adjoining figure, ΔABC is a right-angled triangle, right-angled at B; ABDE and ACGF are the squares. If BH is perpendicular to FG.
Prove that:
- area (ΔΕAC) = area (ΔΒΑF).
- area (◻ABDE) = area (◻AIHF).

The diagonals AC and BD of a parallelogram ABCD intersect at ‘O’. A straight line through ‘O’ meets AB at P and DC at Q.
Prove that: area (◻APQD) = `1/2` × area (◻ABCD).

In the adjoining figure, ABCDE is a pentagon in which EG is drawn parallel to DA meets BA produced at G and CF is drawn parallel to DB meets AB produced at F. Prove that area of ABCDE = area of GDF.

In the adjoining figure, BD = CD and P is a point on AC such that area (ΔAPD) : area (ΔАBD) = 2 : 3.
Find:
- AP : PC.
- area (ΔDCP) : area (ΔАВС).

In the adjoining figure, ABCD and BEFG are two parallelograms.
Prove that : area (◻ABCD) = area (◻BEFG).

ABCD 8 is a parallelogram. E and F are the mid-points of the sides AB and AD respectively. Prove that area (ΔAEF) = `1/8` × area (◻ABCD).
In ΔAВC; E and F are the mid-points of sides AB and AC respectively. If FB and CE intersect at point ‘O’, prove that area (ΔOBC) = area (◻AEOF).
In the adjoining figure, ABCD and ABFE are two parallelograms.
Prove that: area (ABCD) + area (ABFE) = area (EFCD).

In the adjoining figure, PQ || BC, BE || CA and CF || BA. Prove that area of ΔABE = area of ΔACF.

Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई 13 Theorems on Area Exercise 13B [Pages 260 - 261]
Multiple Choice Questions Choose the correct answer from the given four options in each of the following questions :
Two parallelograms are on equal bases and between the same parallel lines. The ratio of their areas is ______.
1 : 1
1 : 2
2 : 1
1 : 3
In the adjoining figure, a parallelogram ABCD is shown. If DM ⊥ AB, DN ⊥ BC, then area of ΔABD is equal to:

`1/2 xx AB xx DN`
`1/2 xx BC xx DN`
`1/2 xx BC xx DM`
`1/2 xx AD xx DM`
In the adjoining figure, a trapezium ABCD is shown in which AB || DC then, ar (ΔAOD) is equal to:

ar (ΔOCD)
ar (ΔAOB)
ar (ΔBCD)
ar (ΔBOC)
A triangle and a rectangle are on the same base and between the same parallel lines. The ratio of their areas is ______.
1 : 1
1 : 2
1 : 3
1 : 4
In the adjoining figure, ABCD is a parallelogram and M is the mid-point of AВ. If ar (|| gm ABCD) = 40 cm2, then ar (ΔADM) is equal to:

5 cm2
20 cm2
15 cm2
10 cm2
The median of a triangle divides it into two ______.
triangles of equal area
congruent triangles
right triangles
isosceles triangles
equilateral triangle
In ΔАВC; the mid-points of the sides BC, CA and AB are D, E and F respectively. The ratio of ar (ΔDEF) and ar (ΔABC) is ______.
1 : 4
1 : 3
1 : 2
1 : 1
In the adjoining figure, a trapezium ABCD is shown in which AB || DC, AB = x and DC = y. If E and F are the mid-points of the sides AD and BC respectively, then ar (ABFE) : ar (EFCD) is:

x : y
(3x + y) : (x + 3y)
(x + 3y) : (3x + y)
(2x + y) : (3x + y)
In the adjoining figure, a parallelogram ABCD is shown in which P divides AB in the ratio 1 : 2. If the area of the parallelogram ABCD is 60 cm2, then area (BPDC) is:

20 cm2
40 cm2
50 cm2
30 cm2
In the adjoining figure, BM = 2CM. If ar (ΔАBC) = 30 cm2, then ar (ΔABM) is:

20 cm2
15 cm2
10 cm2
5 cm2
Solutions for 13: Theorems on Area
![Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 13 - Theorems on Area Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 13 - Theorems on Area - Shaalaa.com](/images/mathematics-english-class-9-icse_6:f26eb985e8254aa987299226050d7c71.jpg)
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 13 - Theorems on Area
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