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Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 10 - Pythagoras Theorem [Latest edition]

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Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 10 - Pythagoras Theorem - Shaalaa.com
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Solutions for Chapter 10: Pythagoras Theorem

Below listed, you can find solutions for Chapter 10 of CISCE Nootan for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई.


Exercise 10AExercise 10B
Exercise 10A [Pages 210 - 212]

Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई 10 Pythagoras Theorem Exercise 10A [Pages 210 - 212]

Exercise 10A | Q 1. (i) | Page 210

Find whether the given sides of the triangle form a right-angled triangle or not:

3 cm, 4 cm and 5 cm

Exercise 10A | Q 1. (ii) | Page 210

Find whether the given sides of the triangle form a right-angled triangle or not:

5 cm, 13 cm and 12 cm

Exercise 10A | Q 1. (iii) | Page 210

Find whether the given sides of the triangle form a right-angled triangle or not:

8 cm, 9 cm and 12 cm

Exercise 10A | Q 2. | Page 210

A rectangular garden is 30 m broad and 40 m long. Find the length of its diagonal.

Exercise 10A | Q 3. | Page 210

A ladder 13 m long rests against a vertical wall. Its top reaches to a window on the wall at 12 m high. Find the distance of the foot of the ladder from the wall.

Exercise 10A | Q 4. | Page 210

Two poles of height 12 m and 24 m stand vertically on a plane ground. If the distance between their tops is 13 m. Find the distance between their feet.

Exercise 10A | Q 5. | Page 210

An aeroplane leaves an airport and flies due North at a speed of 200 km\hr. At the same time another aeroplane leaves the same airport and flies due West at a speed of 150 km\hr. How far apart will be the two aeroplanes after 4 hours?.

Exercise 10A | Q 6. | Page 210

A ladder 25 m long reaches a window which is 15 m above the ground on one side of the street. When it turned to the other side keeping its foot at the same point, it touches a wall at a height of 20 m from the ground. Find the width of the street.

Exercise 10A | Q 7. | Page 210

The side of a rhombus is 10 cm. Its one diagonal is 12 cm. Find the length of other diagonal.

Exercise 10A | Q 8. | Page 210

Find the length of the altitude of an equilateral triangle of side 2a cm. 

Exercise 10A | Q 9. | Page 210

Find the altitude of an equilateral triangle of side `6sqrt(3)` cm.

Exercise 10A | Q 10. | Page 210

In ΔАВC, ∠B = 90°. If AC = (x + 4) cm, BC = (x + 2) cm and AB = (3x + 1) cm, find the sides of triangle.

Exercise 10A | Q 11. | Page 210

In the adjoining figure, ∠PQR = 90°, PR = 10 cm, QR = 6 cm and SR = 9 cm. Find PS.

Exercise 10A | Q 12. | Page 210

In the adjoining figure, ∠RQS = 90°, ∠QPS = 90°, RS = 25 cm, QR = 20 cm, PQ = 9 cm. Find PS.

Exercise 10A | Q 13. | Page 210

In the adjoining figure, DC || AB. BC = 8 cm, AD = 17 cm, CD = 24 cm.

Find

  1. AB 
  2. Area of trapezium ABCD

Exercise 10A | Q 14. | Page 211

ΔАВС is an isosceles triangle in which AB = AC = 17 cm and BC = 16 cm. Find the length of perpendicular drawn from A to BC.

Exercise 10A | Q 15. | Page 211

In the adjoining figure, SR || PQ and ∠PQR = 90°. If PQ = 7 cm, PR = 25 cm and SR = 17 cm, find the length of PS.

Exercise 10A | Q 16. | Page 211

The sides of a right-angled triangle are 2x, x + 5 and 3x + 1. If the hypotenuse is 3x + 1, find the sides of triangle.

Exercise 10A | Q 17. | Page 211

In ΔАВC, ∠ABC = 90° and D is any point on BC. Prove that : AD2 + BC2 = AC2 + BD2.

Exercise 10A | Q 18. | Page 211

In ΔPQR, ∠QPR = 90° and PM ⊥ QR. Prove that : PM2 = QM.RM.

Exercise 10A | Q 19. | Page 211

In a quadrilateral ABCD, ∠B = 90°, AD2 = AB2 + BC2 + CD2, prove that ∠ACD = 90°.

Exercise 10A | Q 20. | Page 211

ΔАВС is a isosceles triangle in which AB = AC and ∠A = 90°. Prove that : BC2 = 2AC2.

Exercise 10A | Q 21. | Page 211

In ΔABC, ∠A = 90° and BC2 = 2AC2, prove that : ΔABC is isosceles.

Exercise 10A | Q 22. | Page 211

In ΔABC, ∠ABC is an acute angle. Prove that : AC2 = AB2 + BC2 – 2BC.BD.

Exercise 10A | Q 23. | Page 211

ΔABC is an equilateral triangle. Side BC is trisected at D. Prove that : 9AD2 = 7AB2.

Exercise 10A | Q 24. | Page 211

In ΔАBC, ∠ABC = 90°. X and Y are mid-points of the sides AB and BC respectively.

Prove that:

  1. CX2 + AY2 = 5XY2
  2. 4(CX2 + AY2) = 5AC2
Exercise 10A | Q 25. | Page 211

In the adjoining figure, AB > AC, BE = EC and ∠ADC = 90°.

Prove that:

  1. AB2 – AC2 = 2BC.ED
  2. AB2 + AC2 = 2(AE2 + BE2)

Exercise 10A | Q 26. | Page 211

In ΔАВС, AB = AC and D is any point on side BC produced. Prove that: AD2 = AB2 + BD · CD.

Exercise 10A | Q 27. | Page 211

Prove that the sum of the squares on the sides of a rhombus is equal to the sum of square on its diagonals.

Exercise 10A | Q 28. | Page 211

The diagonals of a rhombus ABCD intersect each other at O. Prove that: `OA^2 + OC^2 = 2AB^2 - 1/2 BD^2`.

Exercise 10A | Q 29. | Page 211

In ◻ABCD, ∠B = 90° and ∠D = 90°. Prove that : 2AC2 = AB2 + BC2 + CD2 + DA2.

Exercise 10A | Q 30. | Page 211

In the adjoining figure, PQ = QR and ∠PSQ = 90°.

Prove that : PR2 = 2PQ.RS.

Exercise 10A | Q 31. | Page 212

In the adjoining figure, ∠PQR = 90° and XY || QR. If PX : QX = 1 : 2, PQ = 6 cm, PY = 4 cm, find PR and QR.

Exercise 10A | Q 32. | Page 212

If O is any point in the interior of a rectangle, ABCD, prove that : OA2 + OC2 = OB2 + OD2.

Exercise 10B [Page 212]

Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई 10 Pythagoras Theorem Exercise 10B [Page 212]

Multiple Choice Questions Choose the correct answer from the given four options in each of the following questions :

Exercise 10B | Q 1. | Page 212

Each side of an equilateral triangle is 10 cm. The length of the each its altitude is ______.

  • 5 cm

  • `5sqrt(2)  cm`

  • `5sqrt(3)  cm`

  • `3sqrt(5)  cm`

Exercise 10B | Q 2. | Page 212

A ladder 17 m long reaches a window above the ground. If the distance of the foot of ladder from wall is 8 m, the height of the window is ______.

  • 12 m

  • 15 m

  • 12 cm

  • 14 m

Exercise 10B | Q 3. | Page 212

The lengths of the diagonals of a rhombus are 16 cm and 12 cm. The length of the side of rhombus is ______.

  • 8 cm

  • 9 cm

  • 11 cm

  • 10 cm

Exercise 10B | Q 4. | Page 212

In ΔАВC, BC = CA and ∠ACB = 90°. Then correct relation is ______.

  • AB2 = 2AC2

  • 2AB2 = AC2

  • BC2 = 2AC2

  • 2BC2 = AC2

Exercise 10B | Q 5. | Page 212

In a rhombus ABCD, AC2 + BD2 is equal to ______.

  • AB2

  • 2BC2

  • 3CD2

  • 4DA2

Exercise 10B | Q 6. | Page 212

If the sides of a rectangle are 6 cm and 8 cm then the length of its diagonal is ______.

  • 9 cm

  • 10 cm

  • 12 cm

  • 14 cm

Exercise 10B | Q 7. | Page 212

In ΔABC, ∠ACB > 90°. The correct relation is ______.

  • AB2 > BC2 + AC2

  • BC2 > AC2 + AB2

  • AC2 > AB2 + BC2

  • AB2 = BC2 + AC2

Exercise 10B | Q 8. | Page 212

In ΔАВС, ∠ACB < 90°. The correct relation is ______.

  • AB2 = BC2 + AC2

  • BC2 < AC2 + AB2

  • AB2 < BC2 + AC2

  • AB2 > BC2 + AC2

Exercise 10B | Q 9. | Page 212

In ΔABC, AB = AC and BD ⊥ AC then BD2 – CD2 is equal to ______.

  • 2CD·AD

  • 2CD·AC

  • 2AC·BC

  • 2BC·AC

Exercise 10B | Q 10. | Page 212

In ΔАВС, ∠ACB = 90°. P and Q are the points on CA and CB respectively which divides these sides in the ratio 2 : 1. Then 9(AQ2 + BP2) is equal to ______.

  • 5AB2

  • 8AB2

  • 10AB2

  • 13AB2

Solutions for 10: Pythagoras Theorem

Exercise 10AExercise 10B
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 10 - Pythagoras Theorem - Shaalaa.com

Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 10 - Pythagoras Theorem

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