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Chapters
2: Compound Interest
3: Expansions
4: Factorisation
5: Simultaneous Linear Equations
6: Indices/Exponents
7: Logarithms
8: Triangles
▶ 9: Mid-point Theorem
10: Pythagoras Theorem
11: Rectilinear Figures
12: Constructions of Polygons
13: Theorems on Area
14: Circles
15: Statistics
16: Mensuration
17: Trigonometric Ratios
18: Trigonometric Ratios of Some Standard Angles and Complementary Angles
Chapter 19: Co-ordinate Geometry: An Introduction
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Solutions for Chapter 9: Mid-point Theorem
Below listed, you can find solutions for Chapter 9 of CISCE Nootan for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई.
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई 9 Mid-point Theorem Exercise 9A [Pages 194 - 196]
In the adjoining figure, ABC is a triangle in which ∠B = 90°. M and N are the mid-points of sides AB and A, respectively. If AB = 5 cm, BC = 12 cm, find
- Perimeter of ◻MNCB
- Area of ◻MNCB

ΔABC is an isosceles triangle in which AB = AC. If P, Q and R are the mid-points of the sides AB, BC and CA, respectively, prove that ΔPQR is also an isosceles triangle.
In the adjoining figure; P, Q and R are the mid-points of the sides BC, CA and AB, respectively, of ΔABC. Prove that ◻RQPB is a parallelogram.

◻PQRS is a rectangle. If A, B and C are the mid-points of sides PQ, PS and QR, respectively. Prove that AB + AC = `1/2` (PR + SQ).
In the adjoining figure, ABCD is a trapezium in which AB || DC and M is the mid-point of AD. If MN || DC meets BC at N, prove that N is the mid-point of BC.

Show that the straight lines joining the mid-points of the opposite sides of a quadrilateral bisect each other.
In ΔАВС, M and N are the mid-points of AB and AC respectively and R be any point on BC. Use intercept theorem, prove that MN bisects AR.
In the adjoining figure, ◻ABCD is a parallelogram. P is the mid-point of CD and DQ || PB meets CB produced at R.
Prove that:
- AD = `1/2` CR
- DR = 2 PB

In a trapezium ABCD, AB || CD. M and N are two points on AD dividing it into three equal parts. Line segments MP and NQ are parallel to AB which meet BC at P and Q, respectively. Prove that BP = PQ = CQ, i.e., P and Q divide BC into three equal parts.
In the adjoining figure, ABCD is a trapezium in which AB || DC. If M and N are the midpoints of BD and AC, respectively, prove that MN = `1/2` (CD – AB).

In the adjoining figure, ABCD is a parallelogram in which P is the mid-point of DC. If Q is any point on AC such that CQ = `1/4` CA and PQ produced meet BC at R, prove that R is the mid-point of BC.
In ΔABC, D and E are the mid-points of AC and AB, respectively. BD and CE produced meet a line through A parallel to BC at M and N, respectively. Prove that AM = AN.

Show that the quadrilateral formed by joining the mid-points of the adjacent sides of a square is also a square.
In a parallelogram ABCD, the diagonals AC and BD intersect at point O. If P is the mid-point of BC, prove that
- PO || AB
- PO = `1/2` AB
In the adjoining figure; D, E and F are the mid-points of BC, CA and AB, respectively. If AB = 6 cm, BC = 8 cm and AC = 5.6 cm, find :
- perimeter of ΔDEF
- perimeter of ◻ABDE

ABCD is a rhombus. EABF is a straight line such that EA = AB = BF. Prove that ED and FC when produced, meet at right angles.
In the adjoining figure; AP = `1/2` AB and D is the mid-point of AB, Q is the mid-point of PR and DR || BS.
Prove that:
- AQ || DR
- PQ = QR = RS

In the adjoining figure; `CE = 1/2 AC` and D is the mid-point of BC.
Prove that:
- DE = 2DF
- AB = 4CQ

In ΔAВC; D and E are two points on AB such that AD = DE = EB. Through D and E, lines are drawn parallel to AC meet BC at N and M, respectively. Through N and M, lines are drawn parallel to AB meet AC at Q and P. Prove that AP = PQ = CQ.
In the following figure, l || m || n and AB = BC, find:
- PQ if QR = 4 cm
- BO if CR = 6 cm

Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई 9 Mid-point Theorem Exercise 9B [Page 197]
Multiple Choice Questions Choose the correct answer from the given four options in each of the following questions:
In the trapezium ABCD, P and Q are the mid-points of non-parallel sides AD and BC, respectively. Then PQ is equal to ______.
`1/2 (AB - CD)`
`1/2 (AB + CD)`
`1/3 (AB - CD)`
`1/3 (AB + CD)`
In the trapezium ABCD, P and Q are the mid-points of AC and BD respectively AB || CD with AB > CD. Then PQ is equal to ______.
`1/2 (AB - CD)`
`1/2 (AB + CD)`
`1/3 (AB - CD)`
`1/3 (AB + CD)`
In a parallelogram ABCD, the diagonals AC and BD intersect at point M. If P is the mid-point of side AD, then PM is equal to ______.
AB
`1/2 AB`
`1/3 AB`
`1/4 AB`
The quadrilateral formed by joining the mid-points of the sides of a quadrilateral ABCD, taken in order, is a rhombus, if ______.
ABCD is a rhombus
ABCD is a parallelogram
AC = BD
AC ⊥ BD
The quadrilateral formed by joining the mid-point of a quadrilateral ABCD, taken in order is a rectangle, if ______.
ABCD is a rectangle
ABCD is a parallelogram
AC ⊥ BD
AC = BD
In ΔАВC, the mid-points of the sides BC, CA and AB are P, Q and R respectively. PR and BQ meet at X. CR and PQ meet at Y. Then XY is equal to ______.
`1/2 BC`
`1/3 BC`
`1/4 BC`
`1/5 BC`
ΔABC is an isosceles triangle. P, Q and R are the mid-points of the sides BC, CA and AB, respectively. Then ΔPQR is ______.
an isosceles triangle
a scalene triangle
an equilateral triangle
can’t say
Solutions for 9: Mid-point Theorem
![Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 9 - Mid-point Theorem Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 9 - Mid-point Theorem - Shaalaa.com](/images/mathematics-english-class-9-icse_6:f26eb985e8254aa987299226050d7c71.jpg)
Nootan solutions for माठेमटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 9 - Mid-point Theorem
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