मराठी

In the adjoining figure, ∠PQR = 90° and XY || QR. If PX : QX = 1 : 2, PQ = 6 cm, PY = 4 cm, find PR and QR. - Mathematics

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प्रश्न

In the adjoining figure, ∠PQR = 90° and XY || QR. If PX : QX = 1 : 2, PQ = 6 cm, PY = 4 cm, find PR and QR.

बेरीज
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उत्तर

Given:

∠PQR = 90°, XY || QR.

PX : QX = 1 : 2

PQ = 6 cm

PY = 4 cm

Step-wise calculation:

1. From PX : QX = 1 : 2.

Write PX = k, QX = 2k.

So, PQ = PX + QX = 3k.

Thus, 3k = 6 ⇒ k = 2.

Therefore, PX = 2 cm and QX = 4 cm.

2. Because XY || QR, 

ΔPXY ∼ ΔPQR   ...(Corresponding angles equal)

3. Corresponding sides give `(PX)/(PQ) = (PY)/(PR)`. 

Substitute known values:

`2/6 = 4/(PR)` 

⇒ `1/3 = 4/(PR)` 

⇒ PR = 3 × 4

⇒ PR = 12 cm

4. In right ΔPQR right at Q use Pythagoras: 

PR2 = PQ2 + QR2 

So, QR2 = PR2 – PQ2

= 122 – 62

= 144 – 36

= 108

Hence, `QR = sqrt(108)`

= `6sqrt(3) ≈ 10.392  cm`

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पाठ 10: Pythagoras Theorem - Exercise 10A [पृष्ठ २१२]

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नूतन Mathematics [English] Class 9 ICSE
पाठ 10 Pythagoras Theorem
Exercise 10A | Q 31. | पृष्ठ २१२
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