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प्रश्न
ΔАВС is an isosceles triangle in which AB = AC = 17 cm and BC = 16 cm. Find the length of perpendicular drawn from A to BC.
बेरीज
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उत्तर
Given: ΔABC is isosceles with AB = AC = 17 cm and BC = 16 cm.
Step-wise calculation:
1. In an isosceles triangle
The perpendicular from apex A to base BC bisects the base.
So, BD = DC
= `16/2`
= 8 cm
2. In right triangle ABD,
AB is the hypotenuse 17 cm and BD = 8 cm.
So, `AD = sqrt(AB^2 - BD^2)`
= `sqrt(17^2 - 8^2)`
= `sqrt(289 - 64)`
= `sqrt(225)`
= 15 cm
The length of the perpendicular from A to BC is 15 cm.
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