मराठी

Without using distance formula, show that points (–2, –1), (4, 0), (3, 3) and (–3, 2) are vertices of a parallelogram.

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प्रश्न

Without using distance formula, show that points (–2, –1), (4, 0), (3, 3) and (–3, 2) are vertices of a parallelogram.

बेरीज
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उत्तर

Let the vertices of a quadrilateral be A(−2, –1), B(4, 0), C(3, 3), and D(−3, 2).

Slope of AB = `("y"_2 - "y"_1)/("x"_2 - "x"_1)`

= `(0 + 1)/(4 + 2)`

= `1/6`

Slope of DC = `(3 - 2)/(3 + 3)`

= `1/6`

Slope of AB = Slope of DC

That means AB || DC

Slope of BC = `(3 - 0)/(3 - 4)`

= `3/(-1)`

= −3

Slope of AD = `(2 + 1)/(-3 + 2)`

= `3/(-1)`

= −3

∴ Slope of BC = Slope of AD

That means BC || AD

Hence, AB || DC, BC || AD

Hence, ABCD is a parallelogram.

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पाठ 9: Straight Lines - EXERCISE 9.1 [पृष्ठ १५९]

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एनसीईआरटी Mathematics [English] Class 11
पाठ 9 Straight Lines
EXERCISE 9.1 | Q 8. | पृष्ठ १५९

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