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प्रश्न
Find the equation of the straight line passing through (1, 2) and perpendicular to the line x + y + 7 = 0.
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उत्तर
Let m be the slope of the line whose equation is to be found out which is perpendicular to the line x + y + 7 = 0.
The slope of the given line y = (– 1)x – 7 is – 1.
Therefore, using the condition of perpendicularity of lines
We have m × (– 1) = – 1 or m = 1 (Why?)
Hence, the required equation of the line is y – 1
= (1)(x – 2) or y – 1
= x – 2x – y – 1
= 0.
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| Column C1 | Column C2 |
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| (b) Perpendicular to the line (ii) x + y – 5 = 0 x + 2y + 1 = 0 is |
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(iii) x – y –1 = 0 |
| (d) Equally inclined to the axes is | (iv) 3x – 4y – 1 = 0 |
