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प्रश्न
Find the distance between the lines 3x + 4y = 9 and 6x + 8y = 15.
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उत्तर
The equations of lines 3x + 4y = 9 and 6x + 8y = 15.
May be rewritten as 3x + 4y – 9 = 0 and `3x + 4y - 15/2` = 0
Since, the slope of these lines are same and hence they are parallel to each other.
Therefore, the distance between them is given by
`|(9 - 15/2)/sqrt(3^2 + 4^2)| = 3/10`
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