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Find the Equation of the Perpendicular to the Line Segment Joining (4, 3) and (−1, 1) If It Cuts off an Intercept −3 from Y-axis. - Mathematics

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प्रश्न

Find the equation of the perpendicular to the line segment joining (4, 3) and (−1, 1) if it cuts off an intercept −3 from y-axis.

थोडक्यात उत्तर
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उत्तर

Let m be the slope of the required line.
Here, c = y-intercept = \[-\] 3

Slope of the line joining the points (4, 3) and (−1, 1) = \[\frac{1 - 3}{- 1 - 4} = \frac{2}{5}\]

It is given that the required line is perpendicular to the line joining the points (4, 3) and (−1, 1).

\[\therefore m \times \text { Slope of the line joining the points } \left( 4, 3 \right) and \left( - 1, 1 \right) = - 1\]

\[ \Rightarrow m \times \frac{2}{5} = - 1\]

\[ \Rightarrow m = \frac{- 5}{2}\]

Substituting the values of m and c in y = mx + c, we get:

\[y = - \frac{5}{2}x - 3 \]

\[ \Rightarrow 5 x + 2y + 6 = 0\]

Hence, the equation of the required line is 5x + 2y + 6 = 0.

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पाठ 23: The straight lines - Exercise 23.3 [पृष्ठ २१]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 23 The straight lines
Exercise 23.3 | Q 7 | पृष्ठ २१

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