मराठी

The point (4, 1) undergoes the following two successive transformations: (i) Reflection about the line y = x(ii) Translation through a distance 2 units along the positive x-axis Then the fina

Advertisements
Advertisements

प्रश्न

The point (4, 1) undergoes the following two successive transformations: 
(i) Reflection about the line y = x
(ii) Translation through a distance 2 units along the positive x-axis Then the final coordinates of the point are ______.

पर्याय

  • (4, 3)

  • (3, 4)

  • (1, 4)

  • `7/2, 7/2`

MCQ
रिकाम्या जागा भरा
Advertisements

उत्तर

The point (4, 1) undergoes the following two successive transformations: 
(i) Reflection about the line y = x
(ii) Translation through a distance 2 units along the positive x-axis Then the final coordinates of the point are (3, 4).

Explanation:

Let the reflection of A(4, 1) in y = x be B(a, b) mid-point of AB

= `((4 + a)/2, (1 + b)/2)` which lies on y = x

⇒ `(4 + "a")/2 = (1 + b)/2`

⇒ 4 + a = 1 + b

⇒ a – b = – 3  .......(i)

The slope of the line y = x is 1 and slope of AB = `(b - 1)/(a - 4)`

∴ `1((b - 1)/(a - 4)) = - 1`

⇒ b – 1 = – a + 4

⇒ a + b = 5   ....(ii)

Solving equation (i) and equation (ii) we get

a = 1 and b = 4

∴  The point after translation is (1 + 2, 4) or (3, 4).

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 10: Straight Lines - Exercise [पृष्ठ १८२]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 10 Straight Lines
Exercise | Q 37 | पृष्ठ १८२

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

The base of an equilateral triangle with side 2a lies along they y-axis such that the mid point of the base is at the origin. Find vertices of the triangle.


Find the distance between P (x1, y1) and Q (x2, y2) when :

  1. PQ is parallel to the y-axis,
  2. PQ is parallel to the x-axis

Consider the given population and year graph. Find the slope of the line AB and using it, find what will be the population in the year 2010?


Find the values of k for which the line (k–3) x – (4 – k2) y + k2 –7k + 6 = 0 is 

  1. Parallel to the x-axis,
  2. Parallel to the y-axis,
  3. Passing through the origin.

Find the equation of a line drawn perpendicular to the line `x/4 + y/6 = 1`through the point, where it meets the y-axis.


Find the equation of the lines through the point (3, 2) which make an angle of 45° with the line x –2y = 3.


Find the slope of the lines which make the following angle with the positive direction of x-axis:

\[- \frac{\pi}{4}\]


Find the slope of the lines which make the following angle with the positive direction of x-axis:

\[\frac{2\pi}{3}\]


Find the slope of the lines which make the following angle with the positive direction of x-axis: 

\[\frac{3\pi}{4}\]


Find the slope of a line passing through the following point:

 (−3, 2) and (1, 4)


State whether the two lines in each of the following are parallel, perpendicular or neither.

Through (5, 6) and (2, 3); through (9, −2) and (6, −5)


State whether the two lines in each of the following are parallel, perpendicular or neither.

Through (9, 5) and (−1, 1); through (3, −5) and (8, −3)


Using the method of slope, show that the following points are collinear A (4, 8), B (5, 12), C (9, 28).


Show that the line joining (2, −5) and (−2, 5) is perpendicular to the line joining (6, 3) and (1, 1).


Without using Pythagoras theorem, show that the points A (0, 4), B (1, 2) and C (3, 3) are the vertices of a right angled triangle.


Prove that the points (−4, −1), (−2, −4), (4, 0) and (2, 3) are the vertices of a rectangle.


Find the angle between the X-axis and the line joining the points (3, −1) and (4, −2).


Find the value of x for which the points (x, −1), (2, 1) and (4, 5) are collinear.


By using the concept of slope, show that the points (−2, −1), (4, 0), (3, 3) and (−3, 2) are the vertices of a parallelogram.


Find the equation of a straight line  with slope − 1/3 and y-intercept − 4.


Find the angles between the following pair of straight lines:

x − 4y = 3 and 6x − y = 11


Prove that the points (2, −1), (0, 2), (2, 3) and (4, 0) are the coordinates of the vertices of a parallelogram and find the angle between its diagonals.


Prove that the straight lines (a + b) x + (a − b ) y = 2ab, (a − b) x + (a + b) y = 2ab and x + y = 0 form an isosceles triangle whose vertical angle is 2 tan−1 \[\left( \frac{a}{b} \right)\].


The coordinates of the foot of the perpendicular from the point (2, 3) on the line x + y − 11 = 0 are


The reflection of the point (4, −13) about the line 5x + y + 6 = 0 is  


If m1 and m2 are slopes of lines represented by 6x2 - 5xy + y2 = 0, then (m1)3 + (m2)3 = ?


If the line joining two points A(2, 0) and B(3, 1) is rotated about A in anticlock wise direction through an angle of 15°. Find the equation of the line in new position.


The two lines ax + by = c and a′x + b′y = c′ are perpendicular if ______.


The equation of the line passing through (1, 2) and perpendicular to x + y + 7 = 0 is ______.


Find the equation of the line passing through the point (5, 2) and perpendicular to the line joining the points (2, 3) and (3, – 1).


Show that the tangent of an angle between the lines `x/a + y/b` = 1 and `x/a - y/b` = 1 is `(2ab)/(a^2 - b^2)`


A variable line passes through a fixed point P. The algebraic sum of the perpendiculars drawn from the points (2, 0), (0, 2) and (1, 1) on the line is zero. Find the coordinates of the point P.


P1, P2 are points on either of the two lines `- sqrt(3) |x|` = 2 at a distance of 5 units from their point of intersection. Find the coordinates of the foot of perpendiculars drawn from P1, P2 on the bisector of the angle between the given lines.


If p is the length of perpendicular from the origin on the line `x/a + y/b` = 1 and a2, p2, b2 are in A.P, then show that a4 + b4 = 0.


Equations of the lines through the point (3, 2) and making an angle of 45° with the line x – 2y = 3 are ______.


Line joining the points (3, – 4) and (– 2, 6) is perpendicular to the line joining the points (–3, 6) and (9, –18).


The equation of the line through the intersection of the lines 2x – 3y = 0 and 4x – 5y = 2 and

Column C1 Column C2
(a) Through the point (2, 1) is (i) 2x – y = 4
(b) Perpendicular to the line (ii) x + y – 5
= 0 x + 2y + 1 = 0 is
(ii) x + y – 5 = 0
(c) Parallel to the line (iii) x – y –1 = 0
3x – 4y + 5 = 0 is
(iii) x – y –1 = 0
(d) Equally inclined to the axes is (iv) 3x – 4y – 1 = 0

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×