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प्रश्न
Find the equation of a straight line with slope −2 and intersecting the x-axis at a distance of 3 units to the left of origin.
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उत्तर
Here, m = −2
Substituting the value of m in y = mx + c, we get,
y = −2x + c
It is given that the line y = −2x + c intersects the x-axis at a distance of 3 units to the left of the origin.
This means that the required line passes trough the point (−3, 0).
\[\therefore 0 = - 2 \times \left( - 3 \right) + c\]
\[ \Rightarrow c = - 6\]
Hence, the equation of the required line is y = −2x − 6, i.e. 2x + y + 6 = 0
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