मराठी

Which of the Following Functions from a = { X : − 1 ≤ X ≤ 1 } to Itself Are Bijections? (A) F ( X ) = X 2 (B) G ( X ) = Sin ( π X 2 ) (C) H ( X ) = | X | (D) K ( X ) = X 2

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प्रश्न

Which of the following functions from

\[A = \left\{ x : - 1 \leq x \leq 1 \right\}\]

to itself are bijections?

 

 

 

पर्याय

  • \[f\left( x \right) = \frac{x}{2}\]

  • \[g\left( x \right) = \sin\left( \frac{\pi x}{2} \right)\]

  • \[h\left( x \right) = |x|\]

  • \[k\left( x \right) = x^2\]

MCQ
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उत्तर

\[\left( a \right) \text{Range of f}=\left[ \frac{- 1}{2}, \frac{1}{2} \right]\neq A\] 
So, f is not a bijection. 
\[\left( b \right) \text{Range }=\left[ \sin\left( \frac{- \pi}{2} \right), \sin\left( \frac{\pi}{2} \right) \right]=\left[ - 1, 1 \right]=A\] 
So, g is a bijection.
\[\left( c \right) h\left( - 1 \right) = \left| - 1 \right| = 1\] 
\[\text{ and } h\left( 1 \right) = \left| 1 \right| = 1\] 
\[\Rightarrow-1 \text {and 1 have the same images}\] 
So, h is not a bijection. 
\[\]  \[\left( d \right) k\left( - 1 \right) = \left( - 1 \right)^2 = 1\] 
\[\text{and } k \left( 1 \right) = \left( 1 \right)^2 = 1\] 
\[\Rightarrow-1 \text{and 1 have the same images}\] 
So, k is not a bijection.

So, the answer is (b)

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पाठ 2: Functions - Exercise 2.6 [पृष्ठ ७६]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 2 Functions
Exercise 2.6 | Q 15 | पृष्ठ ७६

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