मराठी

Classify the Following Functions as Injection, Surjection Or Bijection : F : R → R, Defined By F(X) = `X/(X^2 +1)`

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प्रश्न

Classify the following function as injection, surjection or bijection :

f : R → R, defined by f(x) = `x/(x^2 +1)`

बेरीज
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उत्तर

f : R → R, defined by f(x) = `x/(x^2 +1)`

Injection test:
Let x and y be any two elements in the domain (R), such that f(x) = f(y).

f(x) = f(y)

`x/(x^2+1) = y/(y^2 + 1)`

xy2+ x = x2y + y

xy2−x2y + x −y = 0

−xy (−y+x)+ 1 (x−y) = 0

(x−y) (1−xy) = 0

x = y or x = `1/y`

So, f is not an injection.
Surjection test:

Let y be any element in the co-domain (R), such that f(x) = y for some element x in R (domain).

f(x) = y

`x/(x^2 +1)= y`

yx2− x+y = 0

`x ((-1) ± sqrt(1-4x^2))/(2y)` if y ≠ 0

`= (1±sqrt(1-4y^2))/(2y) ,`which may not be in R

For example, if y=1, then

`(1±sqrt(1-4))/(2y) = (1± isqrt3)/2`

 which is not in R

So, f is not surjection and f is not bijection.

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पाठ 2: Functions - Exercise 2.1 [पृष्ठ ३१]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 2 Functions
Exercise 2.1 | Q 5.17 | पृष्ठ ३१

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