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प्रश्न
Which of the following cannot exhibit isomerism?
(a) C4H10
(b) C5H12
(c) C3H8
(d) C6H14
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उत्तर
C3H8
C3H8 is the compound which cannot exhibit isomersim, as it contains only 3 carbon atoms. Isomerism is possible only with hydrocarbons containing 4 or more carbon atoms.
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संबंधित प्रश्न
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Two atoms of the same element combine to form a molecule. The bond between them is known as ................ bond.
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(a) Lithium chloride
(b) Ammonium chloride
(c) Calcium chloride
(d) Carbon tetrachloride
Write answer as directed.
Saturated hydrocarbons are classified into three types. Write these names giving one example each.
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An element L consists of molecules.
What type of bonding is present in the particles that make up L?
Name the types of Hydrocarbons.
Complete the following activity.
Write the names of the hydrocarbons for the following structural formula.
(isobutylene, cyclohexane, propene, cyclohexene, cyclopentane, benzene, propyne, isobutane, propane)
| \[\begin{array}{cc} \phantom{..}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\ \phantom{..}|\phantom{....}|\phantom{....}|\\ \ce{H - C - C- C- H}\\ \phantom{.}|\phantom{....}|\phantom{....}|\\ \ce{H - C - H}\\ |\\\ce{H}\end{array}\] |
Two carbon atoms can always form one or two covalent bonds.
