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प्रश्न
Which of the following cannot exhibit isomerism?
(a) C4H10
(b) C5H12
(c) C3H8
(d) C6H14
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उत्तर
C3H8
C3H8 is the compound which cannot exhibit isomersim, as it contains only 3 carbon atoms. Isomerism is possible only with hydrocarbons containing 4 or more carbon atoms.
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संबंधित प्रश्न
List three characteristic properties of covalent compounds.
Give reason why carbon compounds are generally poor conductors of electricity.
Name the element whose one of the allotropic forms is buckminsterfullerene.
Fill in the blank in the following sentence:
In forming N2 molecule, .............. electrons are shared by each atom of nitrogen.
State any two uses of diamond.
what substance is graphite made?
One of the following contains a double bond as well as single bonds. This is:
(a) CO2
(b) O2
(c) C2H4
(d) C2H2
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Draw all possible structural formulae of compound from their molecular formula given below.
C3H8
Explain the following term with example.
Covalent bond
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Polar covalent compounds are good conductors of electricity.
Choose the correct answer from the options given below
Which one is not example of polar covalent compound?
Compound X consists of molecules.
Choose the letter corresponding to the correct answer from the options A, B, C and D given below:
X is likely to have a ______.
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If B is a diatomic gas, write the equation for the direct combination of A and B to form a compound.
Potassium chloride is an electrovalent compound, while hydrogen chloride is a covalent compound, But, both conduct electricity in their aqueous solutions. Explain.
Answer the following question.
What is methane? Draw its electron dot structure. Name the type of bonds formed in this compound. Why are such compounds:
(i) poor conductors of electricity? and
(ii) have low melting and boiling points? What happens when this compound burns in oxygen?
Complete the following activity.
Write the names of the hydrocarbons for the following structural formula.
(isobutylene, cyclohexane, propene, cyclohexene, cyclopentane, benzene, propyne, isobutane, propane)
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Carbon forms four covalent bonds by sharing its four valence electrons with four univalent atoms, e.g. hydrogen. After the formation of four bonds, carbon attains the electronic configuration of
Name the following:
\[\ce{CH3 - CH2CH = CH2}\]

