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प्रश्न
What are the consequences of lanthanoid contraction?
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उत्तर
(1) Resemblance of second and third transition series: This significantly affects the relative properties of the elements coming before and after the lanthanides in the periodic table. It is clear from the following table that there is a regular increase in size from Sc to Y and Y to La.
Table Atomic radii of d-block elements (in pm)
| Sc | Ti | V | Cr | Mn | Fe | Co | Ni | Cu | Zn |
| 164 | 147 | 135 | 129 | 137 | 126 | 125 | 125 | 128 | 137 |
| Y | Zr | Nb | Mo | Tc | Ru | Rh | Pd | Ag | Cd |
| 180 | 160 | 146 | 139 | 136 | 134 | 134 | 137 | 144 | 154 |
| La* | Hf | Ta | W | Re | Os | Ir | Pt | Au | Hg |
| 187 | 158 | 146 | 139 | 137 | 135 | 136 | 138 | 144 | 157 |
Similarly, we can expect a general increase in size in other groups, though after the lanthanoids, the increase in radii from the second to the third transition series is almost negligible.
\[\ce{Ti -> Zr -> Hf}\]
\[\ce{V -> Nb -> Ta}\]
Pairs of primary elements, such as Zr – Hf, Nb – Ta, Mo – W, etc., have similar (almost) sizes, and the properties of these elements are also similar. Hence, as a result of lanthanoid contraction, the elements of the second and third transition series have greater similarity with each other than the elements of the first and second transition series.
(2) Similarity among lanthanides: Due to very small variations in the radii of lanthanoids, their chemical properties are almost similar. Hence, it is very difficult to separate the elements in a pure state. Modern methods based on repeated fractional crystallization or ion exchange techniques separate them based on very small differences in the sizes of their trivalent ions. These methods separate them based on very small differences in elemental properties, such as solubility, complex ion formation, and hydration.
(3) Basicity differences: Due to lanthanoid contraction, the size of lanthanoid ions decreases regularly with an increase in atomic number. As a result of a decrease in size, the covalent character between lanthanoid ions and OH ions increases from La3+ to Lu3+. Hence, the basic strength of hydroxides decreases with an increase in atomic number. Thus, La(OH)3 is the most basic, while Lu(OH)3 is the least basic.
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संबंधित प्रश्न
Define lanthanoid contraction.
What are chemical twins? Write ‘two’ examples.
What are lanthanoids?
Account for the following :
Zr and Hf have almost similar atomic radii.
Name a member of the lanthanoid series which is well known to exhibit +4 oxidation state.
What are the different oxidation states exhibited by the lanthanoids?
Compare the chemistry of actinoids with that of the lanthanoids with special reference to oxidation state.
Compare the chemistry of actinoids with that of the lanthanoids with special reference to atomic and ionic sizes.
Compare the chemistry of actinoids with that of the lanthanoids with special reference to chemical reactivity.
The chemistry of the actinoid elements is not so smooth as that of the Lanthanoids. Justify this statement by giving some examples from the oxidation state of these elements.
Name the members of the lanthanoid series which exhibit +4 oxidation state and those which exhibit +2 oxidation state. Try to correlate this type of behavior with the electronic configurations of these elements.
Write the electronic configuration of the element with the atomic number 61.
Explain effects of lanthanoid contraction.
Explain the cause of Lanthanoids contraction.
What is the action of the following on lanthanoids?
a. water
b. Sulphur, heat
c. nitrogen, heat
What is lanthanoid contraction?
Gadolinium belongs to 4f series. It’s atomic number is 64. Which of the following is the correct electronic configuration of gadolinium?
Which of the following lanthanoids show +2 oxidation state besides the characteristic oxidation state +3 of lanthanoids?
(i) \[\ce{Ce}\]
(ii) \[\ce{Eu}\]
(iii) \[\ce{Yb}\]
(iv) \[\ce{Ho}\]
Although Zr belongs to 4d and Hf belongs to 5d transition series but it is quite difficult to separate them. Why?
Although +3 oxidation states is the characteristic oxidation state of lanthanoids but cerium shows +4 oxidation state also. Why?
Match the statements given in Column I with the oxidation states given in Column II.
| Column I | Column II | |
| (i) | Oxidation state of Mn in MnO2 is | (a) + 2 |
| (ii) | Most stable oxidation state of Mn is | (b) + 3 |
| (iii) | Most stable oxidation state of | (c) + 4 |
| Mn in oxides is | (d) + 5 | |
| (iv) | Characteristic oxidation state of lanthanoids is | (e) + 7 |
On the basis of Lanthanoid contraction, explain the following:
Nature of bonding in \[\ce{La2O3}\] and \[\ce{Lu2O3}\] .
On the basis of Lanthanoid contraction, explain the following:
Trends in the stability of oxo salts of lanthanoids from \[\ce{La}\] to \[\ce{Lu}\].
On the basis of Lanthanoid contraction, explain the following:
Stability of the complexes of lanthanoids.
On the basis of Lanthanoid contraction, explain the following:
Radii of 4d and 5d block elements.
The titanium (Z = 22) compound that does not exist is:-
In lanthanoid the last electron enters (n - 2)f subshell where n is equal to ______.
Zr (Z = 40) and Hf (Z = 72) have similar atomic and ionic radii because of ______.
Write any two consequences of Lanthanoid Contraction.
The lathanide ion that would show colour is ______.
State a reason for the following:
La(OH)3 is more basic than Lu(OH)3.
Why is Mn2+ ion more stable than Fe2+ ion?
(Atomic numbers of Mn = 25 and Fe = 26)
Assertion: There is a continuous increase in size among Lanthanoids with an increase in atomic number.
Reason: Lanthanoids do not show Lanthanoid contraction.
Name an important alloy which contains some of the lanthanoid metals.
Name an important alloy which contains some of the lanthanoid metals. Mention its uses.
The pair of lanthanoid ions which are diamagnetic is:
