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प्रश्न
State the principle involved in separation of DNA fragments using gel electrophoresis.
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उत्तर
As negatively charged molecules, DNA fragments can be forced to migrate in the direction of the anode through a medium or matrix in order to be separated. Through the sifting effect that the agarose gel provides, the DNA fragments separate (resolve) according to their size. Therefore, the size of the fragment determines how far it travels.
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संबंधित प्रश्न
Name the enzymes that are used for the isolation of DNA from bacterial and fungal cells for recombinant DNA technology.
Name and describe the technique that helps in separating the DNA fragments formed by the use of restriction endonuclease
Collect 5 examples of palindromic DNA sequences. Better try to create a palindromic sequence by following base-pair rules.
The total number of nucleotide sequences of DNA that code for a hormone is 1530. The proportion of different bases in the sequence is found to be Adenine = 34%, Guanine = 19%, Cytosine = 23%, Thymine = 19%.
Applying Chargaff’s rule, what conclusion can be drawn?
'Restriction' in Restriction enzyme refers to ______.
Which of the following bacteria is not a source of restriction endonuclease?
Which of the following statements does not hold true for restriction enzyme?
Carefully observe the given picture. A mixture of DNA with fragments ranging from 200 base pairs to 2500 base pairs was electrophoresed on agarose gel with the following arrangement.
(a) What result will be obtained on staining with ethidium bromide? Explain with reason.
(b) The above setup was modified and a band with 250 base pairs was obtained at X.
What change(s) were made to the previous design to obtain a band at X? Why did the band appear at position X?
Given below is the restriction site of a restriction endonuclease Pst-I and the cleavage sites on a DNA molecule.
\[\ce{5' C - T - G - C - A \overset{\downarrow}{-}{G 3'}}\]
\[\ce{3' G\underset{\uparrow}{-} A - C - G - T - C 5'}\]
Choose the option that gives the correct resultant fragments by the action of the enzyme Pst-I.
Hind II always cuts DNA molecules at a particular point called recognition sequence and it consists of ______.
