मराठी

State with Reason Whether the Following Functions Have Inverse : F : {1, 2, 3, 4} → {10} With F = {(1, 10), (2, 10), (3, 10), (4, 10)}

Advertisements
Advertisements

प्रश्न

State with reason whether the following functions have inverse :
f : {1, 2, 3, 4} → {10} with f = {(1, 10), (2, 10), (3, 10), (4, 10)}

Advertisements

उत्तर

f : {1, 2, 3, 4} → {10} with f = {(1, 10), (2, 10), (3, 10), (4, 10)}
We have:
(1) = (2) = (3) = (4) = 10

f is not one-one.

  fis not a bijection.
So, f does not have an inverse.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Functions - Exercise 2.4 [पृष्ठ ६८]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 2 Functions
Exercise 2.4 | Q 1.1 | पृष्ठ ६८

व्हिडिओ ट्यूटोरियलVIEW ALL [5]

संबंधित प्रश्‍न

Show that the function f : R* → R* defined by f(x) = `1/x` is one-one and onto, where R* is the set of all non-zero real numbers. Is the result true, if the domain R* is replaced by N with co-domain being same as R?


Classify the following function as injection, surjection or bijection :

f : R → R, defined by f(x) = x3 + 1


Give examples of two surjective functions f1 and f2 from Z to Z such that f1 + f2 is not surjective.


Show that f : R→ R, given by f(x) = x — [x], is neither one-one nor onto.


Find gof and fog when f : R → R and g : R → R is defined by f(x) = 2x + 3 and  g(x) = x2 + 5 .


Let f = {(3, 1), (9, 3), (12, 4)} and g = {(1, 3), (3, 3) (4, 9) (5, 9)}. Show that gof and fog are both defined. Also, find fog and gof.


Find  fog (2) and gof (1) when : f : R → R ; f(x) = x2 + 8 and g : R → Rg(x) = 3x3 + 1.


Find fog and gof  if : f(x)= x + 1, g (x) = 2x + 3 .


Find f −1 if it exists : f : A → B, where A = {0, −1, −3, 2}; B = {−9, −3, 0, 6} and f(x) = 3 x.


Let A = R - {3} and B = R - {1}. Consider the function f : A → B defined by f(x) = `(x-2)/(x-3).`Show that f is one-one and onto and hence find f-1.

                    [CBSE 2012, 2014]


If f : A → Ag : A → A are two bijections, then prove that fog is an injection ?


If f : R → R is defined by f(x) = x2, find f−1 (−25).


Let f : R → R be defined as  `f (x) = (2x - 3)/4.` write fo f-1 (1) .


What is the range of the function

`f (x) = ([x - 1])/(x -1) ?`


If f : R → R be defined by f(x) = (3 − x3)1/3, then find fof (x).


 \[f : A \to \text{B given by } 3^{ f\left( x \right)} + 2^{- x} = 4\] is a bijection, then

 

 

 

 


The function f : R → R defined by

`f (x) = 2^x + 2^(|x|)` is 

 


A function f from the set of natural numbers to the set of integers defined by

\[f\left( n \right)\begin{cases}\frac{n - 1}{2}, & \text{when n is odd} \\ - \frac{n}{2}, & \text{when n is even}\end{cases}\]

 


If the function

\[f : R \to R\]  be such that

\[f\left( x \right) = x - \left[ x \right]\] where [x] denotes the greatest integer less than or equal to x, then \[f^{- 1} \left( x \right)\]

 


 Let
\[g\left( x \right) = 1 + x - \left[ x \right] \text{and} f\left( x \right) = \begin{cases}- 1, & x < 0 \\ 0, & x = 0, \\ 1, & x > 0\end{cases}\] where [x] denotes the greatest integer less than or equal to x. Then for all \[x, f \left( g \left( x \right) \right)\] is equal to


Let A = ℝ − {3}, B = ℝ − {1}. Let f : A → B be defined by \[f\left( x \right) = \frac{x - 2}{x - 3}, \forall x \in A\] Show that f is bijective. Also, find
(i) x, if f−1(x) = 4
(ii) f−1(7)


Show that the function f: R → R defined by f(x) = `x/(x^2 + 1)`, ∀ ∈ + R , is neither one-one nor onto


Let N be the set of natural numbers and the function f: N → N be defined by f(n) = 2n + 3 ∀ n ∈ N. Then f is ______.


Let f: R → R be the functions defined by f(x) = x3 + 5. Then f–1(x) is ______.


Let A = R – {3}, B = R – {1}. Let f : A → B be defined by `"f"("x") = ("x" - 2)/("x" - 3)` Then, ____________.


The function f : R → R given by f(x) = x3 – 1 is ____________.


If N be the set of all-natural numbers, consider f: N → N such that f(x) = 2x, ∀ x ∈ N, then f is ____________.


Let f : R `->` R be a function defined by f(x) = x3 + 4, then f is ______.


'If 'f' is a linear function satisfying f[x + f(x)] = x + f(x), then f(5) can be equal to:


If f; R → R f(x) = 10x + 3 then f–1(x) is:


The domain of the function `cos^-1((2sin^-1(1/(4x^2-1)))/π)` is ______.


If f: [0, 1]→[0, 1] is defined by f(x) = `(x + 1)/4` and `d/(dx) underbrace(((fofof......of)(x)))_("n"  "times")""|_(x = 1/2) = 1/"m"^"n"`, m ∈ N, then the value of 'm' is ______.


The domain of function is f(x) = `sqrt(-log_0.3(x - 1))/sqrt(x^2 + 2x + 8)` is ______.


Find the domain of sin–1 (x2 – 4).


The trigonometric equation tan–1x = 3tan–1 a has solution for ______.



The given function f : R → R is not ‘onto’ function. Give reason.


Let \(X=\{-1,2,5,8,11\}\), \(Y=\{4,6,8\}\), and suppose different elements \(2,5,8\) of \(X\) have the same image \(4\). What type of function is it with respect to the one-one property?


For \(f:\mathbb{R}\to\mathbb{R}\) defined by \(f(x)=1+x^2\), which statement is correct?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×